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True [87]
3 years ago
10

HELP ASAP!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
bazaltina [42]3 years ago
4 0
I believe the answer should be B
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X^2-11x+30=2 <br> Solve using quadratic formula or factoring
Pavel [41]
X^2-11x+28=0

(x-7)(x-4)=0

x-7=0
x=7

x-4=0
x=4
7 0
3 years ago
which property is illustrated by the equation below (r+s)+t=r+(s+t). A)Associative B)Commutative C)Distributive D)Identity
Lera25 [3.4K]
The associative property of addition is being demonstrated here. The parenthesis are moved around to "associate" or "group" the values into two different pairs.

Note: the associative property of multiplication is very similar and it is
a*(b*c) = (a*b)*c<span />
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3 years ago
Please solve the equation by factorising
Kobotan [32]

Answer:

X= -2/3, 4

Step-by-step explanation:

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2 years ago
The balance in Jake's checking account is $45.55. What would happen if he wrote three checks for $20.00 each?
mrs_skeptik [129]

Answer:

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Step-by-step explanation:

45.55-20-20-20

7 0
2 years ago
Applying Properties of Exponents In Exercise,use the properties of exponents to simplify the expression.
Mkey [24]

Answer:

1.~e^{-2} \\2.~e^{\frac{7}{2}}\\3.~e^8\\4.~e^{\frac{-11}{2}}

Step-by-step explanation:

We have to simplify the given exponential exponents.

Exponential Properties:

e^0 =1\\e^a.e^b = e^{a+b}\\\\\displaystyle\frac{e^a}{e^b} = e^{a-b}\\\\(e^a)^b = e^{ab}\\\\e^{-a} = \frac{1}{e^a}

Simplification takes place in the following manner:

a)

(e^{-3})^\frac{2}{3}\\(e^a)^b = e^{ab}\\=e^{-3\times \frac{2}{3}}\\=e^{-2}

b)

(e^4)(e^{\frac{-1}{2}})\\e^a.e^b = e^{a+b}\\=e^{(4+\frac{-1}{2})} \\= e^{\frac{7}{2}}

c)

(e^{-2})^{-4}\\(e^a)^b = e^{ab}\\= e^{-2\times -4}\\=e^8

d)

(e^{-4})(e^{\frac{-3}{2}})\\e^a.e^b = e^{a+b}\\=e^{(-4+\frac{-3}{2})} \\= e^{\frac{-11}{2}}

4 0
3 years ago
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