All categories

3 years ago

What’s the sum of 20x^2-10x-30

Mathematics

2 answers:

Vladimir [108]3 years ago

8 0

10(x+1)(2x−3) I think

Veronika [31]3 years ago

7 0

10(x1)(2x-3) I think

You might be interested in

Which of the following demonstrates the Distributive Property? (4 points) 3(4a + 2) = 12a + 6 3(4a + 2) = 12a + 2 3(4a + 2) = 4a

Anastasy [175]

1. 12a+6=12a+6
2. 12a+6=12a+2
3. 12a+6=4a+6
4. 12a+6=7a+5

6 0

3 years ago

Two problems here I need solved! I need every step, so please have that with your answers!!

Free_Kalibri [48]

QUESTION 1

We want to solve,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-6x+8}$

We factor the denominator of the fraction on the right hand side to get,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-4x - 2x+8}.$

This implies
$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x(x-4) - 2(x - 4)}.$

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{(x-4)(x - 2)}$

We multiply through by LCM of
$(x-4)(x - 2)$

$(x - 2) + x(x-4) = 2$

We expand to get,

$x - 2 + {x}^{2} - 4x= 2$

We group like terms and equate everything to zero,

${x}^{2} + x - 4x - 2 - 2 = 0$

We split the middle term,

${x}^{2} + - 3x - 4 = 0$

We factor to get,

${x}^{2} + x - 4x- 4 = 0$

$x(x + 1) - 4(x + 1) = 0$

$(x + 1)(x - 4) = 0$

$x + 1 = 0 \: or \: x - 4 = 0$

$x = - 1 \: or \: x = 4$

But
$x = 4$
is not in the domain of the given equation.

It is an extraneous solution.

$\therefore \: x = - 1$
is the only solution.

QUESTION 2

$\sqrt{x+11} -x=-1$

We add x to both sides,

$\sqrt{x+11} =x-1$

We square both sides,

$x + 11 = (x - 1)^{2}$

We expand to get,

$x + 11 = {x}^{2} - 2x + 1$

This implies,

${x}^{2} - 3x - 10 = 0$

We solve this quadratic equation by factorization,

${x}^{2} - 5x + 2x - 10 = 0$

$x(x - 5) + 2(x - 5) = 0$

$(x + 2)(x - 5) = 0$

$x + 2 = 0 \: or \: x - 5 = 0$

$x = - 2 \: or \: x = 5$

But
$x = - 2$
is an extraneous solution

$\therefore \: x = 5$

7 0

3 years ago

Y = x - 1

romanna [79]

Answer: The correct answer is the third option, (-3,-4).

Step-by-step explanation: You plug in 2x + 2 for y, given that y = 2x + 2.

2x+2 = x - 1

x = -3

Now, you plug in -3 for x in an equation.

y = -3 - 1

y = -4.

(-3, -4)

4 0

2 years ago

Read 2 more answers

How do i graph negative square roots on a number line

DerKrebs [107]

Answer:

see below

Step-by-step explanation:

On the real number line you can't

to graph them you have to make a Cartesian plane

with x= the real numbers

and y= the imaginary numbers

8 0

3 years ago

Which of these strategies would eliminate a variable in the system of equations? 8x+8y=2 8x+5y=1 Add the equations. (Choice B

harkovskaia [24]

Answer:

B. Subtract the bottom equation from the top equation.

Step-by-step explanation:

When looking at the two equations:

8x + 8y = 2

8x + 5y = 1

We can easily get rid of the x variable by subtracting the two equations from each other since the terms are equivalent. This would allow us to solve for the y value, which we could plug into the an equation to solve for the x value.

7 0

3 years ago

Read 2 more answers