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Snezhnost [94]
3 years ago
6

Which statement is true regarding the parallel and perpendicular lines in the diagram

Mathematics
1 answer:
zalisa [80]3 years ago
7 0
Diagram Please......................,
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A pyramid has a base area of 28 cm² and a height of 24. 9 cm. What is the volume of the pyramid? Enter your answer as a decimal
qaws [65]

The volume of the Pyramid whose height be 24.9 cm and the base area be 28 cm² is 232.4 cm³.

<h3>What is Geometry?</h3>

It deals with the size of geometry, region, and density of the different forms both 2D and 3D.

Given

A pyramid has a base area of 28 cm² and a height of 24.9 cm.

The volume of the pyramid is given by

\rm Volume = \dfrac{1}{3} Area\ of \ the \ base \ *  \ Height

Then the volume will be

\rm Volume = \dfrac{1}{3}* 28 *  24.9\\\\Vomlue = 8.3*28\\\\\rm Volume = 232.4

Thus, the volume of the Pyramid is 232.4 cm³.

More about the geometry link is given below.

brainly.com/question/7558603

4 0
3 years ago
(10)9-(10)11 simplify the expression
xeze [42]

Answer:

-20.

Step-by-step explanation:

(10)9 - (10)11

By the Distribute Law this is :

10(9 - 11)

= 10 * -2

= -20.

4 0
3 years ago
How to solve 3/4 x=60
Snezhnost [94]

Answer:

80

Step-by-step explanation

Standard form:

3

4

x − 60 = 0

Factorization:

3

4

(x − 80) = 0

Solutions:

x = 240

3

= 80

8 0
4 years ago
Read 2 more answers
Help pleaseeee!!!!!!!!! I’ll mark brainliest!!!!!
Margarita [4]

Answer:

i believe it is D side angle side

Step-by-step explanation:

7 0
3 years ago
A car was purchased for $25,000. Research shows that the car has an average yearly depreciation rate of 18.5%. Create a function
vitfil [10]

Answer:

V(t) = 25000 * (0.815)^t

The depreciation from year 3 to year 4 was $2503.71

Step-by-step explanation:

We can model V(t) as an exponencial function:

V(t) = Vo * (1+r)^t

Where Vo is the inicial value of the car, r is the depreciation rate and t is the amount of years.

We have that Vo = 25000, r = -18.5% = -0.185, so:

V(t) = 25000 * (1-0.185)^t

V(t) = 25000 * (0.815)^t

In year 3, we have:

V(3) = 25000 * (0.815)^3 = 13533.58

In year 4, we have:

V(4) = 25000 * (0.815)^4 = 11029.87

The depreciation from year 3 to year 4 was:

V(3) - V(4) = 13533.58 - 11029.87 = $2503.71

7 0
3 years ago
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