Help pleaseeee!!!!!!!!! I’ll mark brainliest!!!!!

Fractions and properties of addition

Softa [21]

Answer:

Associative Property

Commutative Property

Distributive Property

Identity Property

Step-by-step EXPLANATION

ASSOCIATIVE PROPERTY

In this property, irrespective of the regrouping between a number and the addent within a bracket, the sum, value does not change.

For example:

(A + B) + C = A + ( B + C)

COMMUTATIVE PROPERTY

In commutative Property, you will always get thesame results after changing the order or position of the addent.

For example:

A + B = A + B

Also,

A + B = B + A

DISTRIBUTIVE PROPERTY

Basically here, please note that, the sum (addition) of two numbers times a Third one is always equal to the sum of these numbers times the third one.

For Example:

A x (B + C) = AB + AC

IDENTITY PROPERTY

This property is the easiest of all, it simply says that "Add a number to Zero must always be that number".

For example:

A + 0 = A

B + 0 = B

C + 0 = C

HOPE THIS HELPED!

3 0

2 years ago

What is the domain of f(x) = 5- 7?

anyanavicka [17]

Answer:

c

Step-by-step explanation:

hi

6 0

2 years ago

What is the measure of minor arc BD?

Vaselesa [24]

Answer:

$minor\ arc\ BD=100^o$

Step-by-step explanation:

The picture of the question in the attached figure

we know that

A circumscribed angle is the angle made by two intersecting tangent lines to a circle

so

In this problem

BC and CD are tangents to the circle

BC=CD ----> by the Two Tangent Theorem

That means

Triangle ABC and Triangle ADC are congruent

so

$m\angle BAC=m\angle DAC$

Find the measure of angle BAC

In the right triangle ABC

$m\angle BAC+m\angle BCA=90^o$

substitute given value

$m\angle BAC+40^o=90^o$

$m\angle BAC=90^o-40^o=50^o$

Find the measure of angle BAD

$m\angle BAD=2m\angle BAC$

$m\angle BAD=2(50^o)=100^o$

Find the measure of minor arc BD

we know that

$minor\ arc\ BD=m\angle BAD$ -----> by central angle

therefore

$minor\ arc\ BD=100^o$

8 0

3 years ago

Read 2 more answers

Fine each angle measure to the nearest degrees. Sin W=0.7771

monitta

Answer:

51 deg

Step-by-step explanation:

Sin W=0.7771

$W = sin^{-1} 0.7771$ (use calculator)

W = 50.996 deg

= 51 deg (to nearest degree)

3 0

3 years ago

Find the x-coordinates of any relative extrema and inflection point(s) for the function f(x)= 6x^1/3 + 3x^4/3. You must justify

irina [24]

Answer:

x-coordinates of relative extrema = $\frac{-1}{2}$

x-coordinates of the inflexion points are 0, 1

Step-by-step explanation:

$f(x)=6x^{\frac{1}{3}}+3x^{\frac{4}{3}}$

Differentiate with respect to x

$f'(x)=6\left ( \frac{1}{3} \right )x^{\frac{-2}{3}}+3\left ( \frac{4}{3} \right )x^{\frac{1}{3}}=\frac{2}{x^{\frac{2}{3}}}+4x^{\frac{1}{3}}$

$f'(x)=0\Rightarrow \frac{2}{x^{\frac{2}{3}}}+4x^{\frac{1}{3}}=0\Rightarrow x=\frac{-1}{2}$

Differentiate f'(x) with respect to x

$f''(x)=2\left ( \frac{-2}{3} \right )x^{\frac{-5}{3}}+\frac{4}{3}x^{\frac{-2}{3}}=\frac{-4x^{\frac{2}{3}}+4x^{\frac{5}{3}}}{3x^{\frac{2}{3}}x^{\frac{5}{3}}}\\f''(x)=0\Rightarrow \frac{-4x^{\frac{2}{3}}+4x^{\frac{5}{3}}}{3x^{\frac{2}{3}}x^{\frac{5}{3}}}=0\Rightarrow x=1$

At x = $\frac{-1}{2}$ ,

$f''\left ( \frac{-1}{2} \right )=\frac{4\left ( -1+4\left ( \frac{-1}{2} \right ) \right )}{3\left ( \frac{-1}{2} \right )^{\frac{5}{3}}}>0$

We know that if $f''(a)>0$ then x = a is a point of minima.

So, $x=\frac{-1}{2}$ is a point of minima.

For inflexion points:

Inflexion points are the points at which f''(x) = 0 or f''(x) is not defined.

So, x-coordinates of the inflexion points are 0, 1

7 0

3 years ago