Answer:
225 ft^2
Step-by-step explanation:
From what we have in the question, we have 60 ft of fencing
To maximize the area, we will need to have a square
For a square, the length of all sides are equal
Let us call one of the sides s
Thus, from the perimeter of the square;
4s = 60
s = 60/4
s = 15 ft
The area is thus, the product of the side length of the square
15 * 15 = 225 ft^2
Answer:
x=9
Step-by-step explanation:
FE is 3x-7
since ΔABC≅ΔDEF the equivalent of FE is CB, or BC...which is 20
3x-7=20
3x=27
x=9
(5x + 2)/(3x + 32) = 24/48
(5x + 2)/(3x + 32) = 1/2
2(5x + 2) = 3x + 32
10x + 4 = 3x + 32
7x = 28
x = 4
Mid segment = 5(4) + 2 = 20 + 2 = 22
Answer
22
