We are looking to find P(X>60 students)
X is normally distributed with mean 50 and standard deviation 5
We need to find the z-score of 60 students

To find the probability of P(Z>2), we can do 1 - P(Z<2)
So we read the probability when Z<2 which is 0.9772, then subtract from one we get 0.0228
The number of students that has score more than 60 is 0.0228 x 1000 = 228 students
<h2>•5×7^2</h2>
<em>HOPE</em><em> </em><em>ITS</em><em> </em><em>HELPFUL</em><em> </em>^_^
<h2>
•RHONA</h2>
The correct answer for this question is this one: "B. the quotient 5 cubed over 5 to the fourth, raised to the negative 3 power"
<span>A. 5 times the quotient 5 cubed over two-fifths, raised to the second power
B. the quotient 5 cubed over 5 to the fourth, raised to the negative 3 power
C. 5 to the negative 2 over 5 to the negative 5
E. 5 times the quotient 5 to the 5 over 5 cubed</span>
Answer:
Therefore , the factors of 24 are = 1,2,3,4,6,12 and 24
Step-by-step explanation:
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#hope it helps you..
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