Answer:
2
Step-by-step explanation:
substitute n=1 and n=3 in the given equation
1 st term is (1)^2-1-2 = 1 -1 -2 = -2
3rd term is (3)^2-3-2 = 9-3-2=4
sum of 1st and 3rd term is -2 + 4 = 2
Step-by-step explanation:
x=c-y. / x=py/q
y=c-x. / y=xq/p
The value of the given cone with a volume of 144 has a width is 6 inches.
We have given that,
A box of cereal has a volume of 144 inches squared.
The height of the cereal box is 12 inches, and the depth is 2 inches.
The volume of cone = 144 inches squared.
height=12 inches
depth=2inches
<h3>What is the formula of the cube?</h3>
Area of a cube = V = L * W * H
L-length
W-width
H-height
We have to determine the width cereal box.
Plug the given values in the formula
V = L * W * H
144=2×12×width
Width=144/24
Width=6inches
Therefore the value of the width is 6 inches.
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<h3>Answer:</h3>
Yes, ΔPʹQʹRʹ is a reflection of ΔPQR over the x-axis
<h3>Explanation:</h3>
The problem statement tells you the transformation is ...
... (x, y) → (x, -y)
Consider the two points (0, 1) and (0, -1). These points are chosen for your consideration because their y-coordinates have opposite signs—just like the points of the transformation above. They are equidistant from the x-axis, one above, and one below. Each is a <em>reflection</em> of the other across the x-axis.
Along with translation and rotation, <em>reflection</em> is a transformation that <em>does not change any distance or angle measures</em>. (That is why these transformations are all called "rigid" transformations: the size and shape of the transformed object do not change.)
An object that has the same length and angle measures before and after transformation <em>is congruent</em> to its transformed self.
So, ... ∆P'Q'R' is a reflection of ∆PQR over the x-axis, and is congruent to ∆PQR.
