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3 years ago

Plz help ill give you brainlist

Mathematics

1 answer:

Step2247 [10]3 years ago

7 0

------------------------------------
Find Radius
------------------------------------
Radius = Diameter ÷ 2
Radius = 27 ÷ 2
Radius = 13.5 cm

------------------------------------
Find Area
------------------------------------
Area of circle x = πr²
Area of circle x = 3.14 x 13.5²
Area of circle x = 572.265 cm²

------------------------------------
Find Radius
------------------------------------
Radius = Diameter ÷ 2
Radius = 12 ÷ 2
Radius = 6 cm

------------------------------------
Find Area
------------------------------------
Area of circle y = πr²
Area of circle y = 3.14 x 6²
Area of circle y = 113.04 cm²

------------------------------------
Compare the area
------------------------------------
572.265 - 113.04 = 459.23 cm²

------------------------------------------------------------------------
Answer: Circle x is 459.23cm² greater than circle y.
------------------------------------------------------------------------

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F(x)=-x^2+x f(x)=−x Find f(−1)

STALIN [3.7K]

Answer:

Step 1: Set x to -1 in the first equation

$f(x) = -x^2 + x$

$f(-1) = -(-1)^2 + (-1)$

$f(-1) = -(1) - 1$

$f(-1) = -1 - 1$

$f(-1) = -2$

Step 2: Set x to -1 in the second equation

$f(x) = -x$

$f(-1) = -(-1)$

$f(-1) = 1$

5 0

3 years ago

Find the amount in the bank after 7 years if interest is compounded quarterly?

qwelly [4]

Answer:

a) amount in the bank after 7 years if interest is compounded quarterly is $6,605

b) amount in the bank after 7 years if interest is compounded quarterly is $6,612.57

Step-by-step explanation:

We are given:

Principal Amount P= 5000

Rate r= 4% = 0.04

time t = 7 years

The formula used is: $A=P(1+\frac{r}{n})^{nt}$

where A is future value, P is principal amount, r is rate, n is compounded value and t is time

a) Find the amount in the bank after 7 years if interest is compounded quarterly?

If interest is compounded quarterly then n = 4

Using values given in question and finding A

$A=P(1+\frac{r}{n})^{nt}\\A=5000(1+\frac{0.04}{4})^{4*7} \\A=5000(1+0.01)^{28}\\A=5000(1.01)^{28}\\A=5000(1.321)\\A=6,605$

So, amount in the bank after 7 years if interest is compounded quarterly is $6,605

b) Find the amount in the bank after 7 years if interest is compounded monthly?

If interest is compounded quarterly then n = 12

Using values given in question and finding A

$A=P(1+\frac{r}{n})^{nt}\\A=5000(1+\frac{0.04}{12})^{12*7} \\A=5000(1+0.003)^{84}\\A=5000(1.003)^{84}\\A=5000(1.322)\\A=6,612.57$

So, amount in the bank after 7 years if interest is compounded quarterly is $6,612.57

6 0

3 years ago

()) A rectangular piece of paper has a perimeter of 22 inches and an area of 28 square

Natasha2012 [34]

Given:

Perimeter of a rectangular paper = 22 inches.

Area of the rectangular paper = 28 square inches.

To find:

The dimensions of the rectangular paper.

Solution:

Let l be the length and w be the width of the rectangular paper.

Perimeter of a rectangle is:

$P=2(l+w)$

Perimeter of a rectangular paper is 22 inches.

$2(l+w)=22$

$l+w=\dfrac{22}{2}$

$l=11-w$ ...(i)

Area of a rectangle is:

$A=lw$

Area of the rectangular paper is 28 square inches.

$28=lw$

Using (i), we get

$28=(11-w)w$

$28=11w-w^2$

$w^2-11w+28=0$

Splitting the middle term, we get

$w^2-7w-4w+28=0$

$w(w-7)-4(w-7)=0$

$(w-7)(w-4)=0$

Using zero product property, we get

$(w-7)=0\text{ and }(w-4)=0$

$w=7\text{ and }w=4$

If $w=7$ , then by using (i)

$l=11-7$

$l=4$

If $w=4$ , then by using (i)

$l=11-4$

$l=7$

Therefore, the dimensions of the paper are either $7\times 4$ or $4\times 7$ .

5 0

3 years ago

If a box of 15 cookies cost $9 what is the cost for 1 cookie?

shtirl [24]

Divide 9 by 15.

9/15= 0.6

Each cookie costs 60 cents.

I hope this helps!
~kaikers

4 0

4 years ago

Read 2 more answers

The time to failure (in hours) for a laser in a cytometry machine is modeled by an exponential distribution with . Round the ans

wariber [46]

Answer:

a)e^-(λ20891)

b)1-e^-(λ30598)

c)1-e^-(λ30598)-e^-(λ20891)

Step-by-step explanation:

The probability density function (pdf) of an exponential distribution is

f(x,λ)=λe^-(λx) for x>0, and 0 for x<0

The cumulative distribution function is given by

F(x,λ)=1-e^-(λx) for x>0, and 0 for x<0

P(X≥20891)=1-P(X≤20891)=1-F(20891,λ)=e^-(λ20891)

P(X≤30598)=F(30598,λ)=1-e^-(λ30598)

P(20891≤X≤30598)=F(30598,λ)-(20891,λ)=1-e^-(λ30598)-e^-(λ20891)

5 0

3 years ago