Answer:
<u>Step 1: Set x to -1 in the first equation
</u>





<u>Step 2: Set x to -1 in the second equation
</u>



Answer:
a) amount in the bank after 7 years if interest is compounded quarterly is $6,605
b) amount in the bank after 7 years if interest is compounded quarterly is $6,612.57
Step-by-step explanation:
We are given:
Principal Amount P= 5000
Rate r= 4% = 0.04
time t = 7 years
The formula used is: 
where A is future value, P is principal amount, r is rate, n is compounded value and t is time
a) Find the amount in the bank after 7 years if interest is compounded quarterly?
If interest is compounded quarterly then n = 4
Using values given in question and finding A

So, amount in the bank after 7 years if interest is compounded quarterly is $6,605
b) Find the amount in the bank after 7 years if interest is compounded monthly?
If interest is compounded quarterly then n = 12
Using values given in question and finding A

So, amount in the bank after 7 years if interest is compounded quarterly is $6,612.57
Given:
Perimeter of a rectangular paper = 22 inches.
Area of the rectangular paper = 28 square inches.
To find:
The dimensions of the rectangular paper.
Solution:
Let l be the length and w be the width of the rectangular paper.
Perimeter of a rectangle is:

Perimeter of a rectangular paper is 22 inches.


...(i)
Area of a rectangle is:

Area of the rectangular paper is 28 square inches.

Using (i), we get



Splitting the middle term, we get



Using zero product property, we get


If
, then by using (i)


If
, then by using (i)


Therefore, the dimensions of the paper are either
or
.
Divide 9 by 15.
9/15= 0.6
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~kaikers
Answer:
a)e^-(λ20891)
b)1-e^-(λ30598)
c)1-e^-(λ30598)-e^-(λ20891)
Step-by-step explanation:
The probability density function (pdf) of an exponential distribution is
f(x,λ)=λe^-(λx) for x>0, and 0 for x<0
The cumulative distribution function is given by
F(x,λ)=1-e^-(λx) for x>0, and 0 for x<0
P(X≥20891)=1-P(X≤20891)=1-F(20891,λ)=e^-(λ20891)
P(X≤30598)=F(30598,λ)=1-e^-(λ30598)
P(20891≤X≤30598)=F(30598,λ)-(20891,λ)=1-e^-(λ30598)-e^-(λ20891)