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mezya [45]
3 years ago
9

Rhombus ABCD has a diagonal BD¯¯¯¯¯. m∠ADB=(5x+10)° m∠CDB=(4x+19)° What is the m∠ADC ? Enter your answer in the box º

Mathematics
1 answer:
Lorico [155]3 years ago
6 0

Answer:

110°

Step-by-step explanation:

5x+10=4x+19

5x-4x =19-10

x = 9

m <em>L</em><em> </em>ADB = 5(9)+10=45+10=55°

so m <em>L</em><em> </em>ADC = 2×55° = 110°

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