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Lelechka [254]
4 years ago
14

Drag each tile to the correct box. Not all tiles will be used

Mathematics
1 answer:
Anni [7]4 years ago
4 0

Acceleration: a=\frac{2(vt-s)}{t^2}

Step-by-step explanation:

For an object in uniformly accelerated motion, we can use the so-called SUVAT equations.

One of them is:

s=vt-\frac{1}{2}at^2

where

s is the displacement

v is the final velocity

t is the time

a is the acceleration

Here we want to re-arrange the equation to find the acceleration. We start by adding -vt on both sides of the equation:

s-vt=-\frac{1}{2}at^2

Now we change sign on both sides:

\frac{1}{2}at^2=vt-s

And finally we multiply by 2 and divide by t^2 on both sides, so we get:

a=\frac{2(vt-s)}{t^2}

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

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A 96 inch stick breaks into two pieces in the ratio of 3:5. How big is each piece?
Svetlanka [38]
40 cm.

let the length of the first part be 3x, second part be 4x, third part be 5x.

where x is a positive length in cm.

why 3x,4x and 5x ?

so that the ratio of lengths of the 3 parts be 3:4:5.

total length of the stick = 3x + 4x + 5x = 12x=96cm

so x=96/12 = 8cm

therefore the largest part of the stick (5x)= 5*8 =40cm
6 0
3 years ago
Solve the system using elimination.<br><br> 2x + 3y = 17<br> x + 5y = 19
ale4655 [162]

\left\{\begin{array}{ccc}2x+3y=17\\x+5y=19&|\text{multiply both sides by (-2)}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}2x+3y=17\\-2x-10y=-38\end{array}\right}\qquad\text{add both sides of equations}\\.\qquad\qquad-7y=-21\qquad\text{divide both sides by (-7)}\\.\qquad\qquad \boxed{y=3}\\\\\\\text{Substitute the value of y to the second equation}\\\\x+5(3)=19\\\\x=15=19\qquad\text{subtract 15 from both sides}\\\\\boxed{x=4}\\\\Answer:\ x=4\ and\ y=3.

5 0
3 years ago
Can someone help me!<br> if something cost $4.90 due to a 14% discount what is the original price
Vlad [161]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
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n200080 [17]
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This is simple. First, you would need to find the unit rate, which is 5.5
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I hope I helped :)
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Irina18 [472]
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h >= x

hence depending on the amount ot hours needed to practice each week, you have to set them to be the minimum, and any other larger quantity satisfies the proposition as well.
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