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zimovet [89]
3 years ago
15

8wsquared2

8w" alt="8w {2 }^{2} - 18w" align="absmiddle" class="latex-formula">
-18w
Mathematics
1 answer:
balandron [24]3 years ago
4 0

{\text{Here, we have the algebraic expression}} \hfill \\ 8w \times {2^2} - 18w \hfill \\ {\text{For simplifying the expression, first we solve the exponent part,}} \hfill \\ {\text{and then the resultant will be multiply with the monomial }}18w \hfill \\ 8w \times {2^2} - 18w \hfill \\ = 8 \times w \times {2^2} - 18w \hfill \\= \left( {8 \times {2^2}} \right) \times w - 18w\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\left[ {\because \,{\text{By associative law }}a \times \left( {b \times c} \right) = \left( {a \times b} \right) \times c} \right] \hfill \\   = \left( {8 \times 4} \right) \times w - 18w \hfill \\   = 32 \times w - 18w \hfill \\= 32w - 18w \hfill \\= 14w \hfill \\

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Assume that adults have IQ scores that are normally distributed with a mean of mu equals μ=105 and a standard deviation sigma eq
Over [174]

The probability that a randomly selected adult has an IQ less than

135 is 0.97725

Step-by-step explanation:

Assume that adults have IQ scores that are normally distributed with a mean of mu equals μ = 105 and a standard deviation sigma equals σ = 15

We need to find the probability that a randomly selected adult has an IQ less than 135

For the probability that X < b;

  • Convert b into a z-score using z = (X - μ)/σ, where μ is the mean and σ is the standard deviation
  • Use the normal distribution table of z to find the area to the left of the z-value ⇒ P(X < b)

∵ z = (X - μ)/σ

∵ μ = 105 , σ = 15 and X = 135

∴ z=\frac{135-105}{15}=2

- Use z-table to find the area corresponding to z-score of 2

∵ The area to the left of z-score of 2 = 0.97725

∴ P(X < 136) = 0.97725

The probability that a randomly selected adult has an IQ less than

135 is 0.97725

Learn more:

You can learn more about probability in brainly.com/question/4625002

#LearnwithBrainly

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