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zimovet [89]
3 years ago
15

8wsquared2

8w" alt="8w {2 }^{2} - 18w" align="absmiddle" class="latex-formula">
-18w
Mathematics
1 answer:
balandron [24]3 years ago
4 0

{\text{Here, we have the algebraic expression}} \hfill \\ 8w \times {2^2} - 18w \hfill \\ {\text{For simplifying the expression, first we solve the exponent part,}} \hfill \\ {\text{and then the resultant will be multiply with the monomial }}18w \hfill \\ 8w \times {2^2} - 18w \hfill \\ = 8 \times w \times {2^2} - 18w \hfill \\= \left( {8 \times {2^2}} \right) \times w - 18w\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\left[ {\because \,{\text{By associative law }}a \times \left( {b \times c} \right) = \left( {a \times b} \right) \times c} \right] \hfill \\   = \left( {8 \times 4} \right) \times w - 18w \hfill \\   = 32 \times w - 18w \hfill \\= 32w - 18w \hfill \\= 14w \hfill \\

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The weights, in pounds, for 15 horses in a stable were
sweet-ann [11.9K]

The median value remains unchanged if the four values are reported using the corrected weight.

The correct answer is an option (B)

We know that the mean is calculated by finding the sum of all the weights of the horses and then dividing by the number of horses.

Decreasing one of the weights would decrease the sum and therefore decrease the mean.

So, the choice A is incorrect.

We know that the range is the difference between the highest and lowest weights, so decreasing the lowest weight would increase the range.

So, the choice C is incorrect.

We know that the Standard deviation is calculated based on the mean weight of the horses.

And decreasing one of the weights decreases the mean and therefore would affect the standard deviation.

So, the choice D is incorrect.

Now, as we know the median the middle value in a sorted, ascending or descending list of values.

So, the median weight is found by ordering the horses’ weights from least to greatest and then determining the middle value from this list of weights.

Decreasing the value for the horse with the lowest weight doesn’t affect the median since it’s still the lowest value.

Therefore, the median value remains unchanged if the four values are reported using the corrected weight.

The correct answer is an option (B)

Learn more about the median here:

brainly.com/question/28060453

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7 0
1 year ago
A box contains cards bearing numbers from 6 to 70. If one card is drawn at random from the box, find the probability that it bea
777dan777 [17]

Answer:

a) 4/65 b) 13/65 c) 12/65 d) 19/65

Step-by-step explanation:

Probability is the likelihood or chance that an event might occur.

Probability = expected outcome of event/Total outcome of event

If a box contains cards bearing numbers from 6 to 70, the total outcome will be the total number present from 6 to 70 which is 65

a) The amount of one digit number we have are 4 i.e {6,7,8,9}. This will be our expected outcome in this case.

The probability that the number drawn bears a one digit number will be 4/65

b) For numbers divisible by 5, the numbers that are divisible by 5 from the number drawn are {10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70}

The total expected outcome in this case = 13

The probability that the number drawn is divisible by 5 = 13/65

c) For odd numbers less than 30, they are {7,9,11,13,15,17,19,21,23,25,27,29}

The total expected outcome in this case = 12

The probability that the number drawn are odd numbers less than 30 = 12/65

d) For composite number between 50 and 70, this are numbers that are within this range and they includes {51,52,53,54,55,56,57,58,59,60,61,62,63,64,65,66,67,68,69}

The total expected outcome in this case = 19

The probability that the number drawn are composite numbers between 50 and 70= 19/65

8 0
3 years ago
The formula gives the height of an object in free fall at time t and acceleration g.
ale4655 [162]

t must equal √2h/g but I don't see that in the choices above

3 0
3 years ago
Jaime needs to buy a new refrigerator for his apartment. He found what he needed for
AleksAgata [21]
Maybe after the dog walked the street
5 0
3 years ago
5y(2x-1)=y(x+2)+20, x=3​
Shkiper50 [21]

Answer:

y=1

Step-by-step explanation:

5y(2x-1)=y(x+2)+20, x=3

5y(2(3)-1)=y(3+2)+20

5y(6-1)=y(5)+20

5y(5)=5y+20

25y=5y+20

25y-5y=20

20y=20

y=20/20

y=1

4 0
3 years ago
Read 2 more answers
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