Answer:
False
Step-by-step explanation:
This is because there both above sea level and 50-17=33 not -33
Answer:
WHATS THE question ???
PLS SAY I WILL TRY TO HELP U
Okay, Tommy runs in a positive y direction at 3mph, and his position can be expressed as:
T=3t
Then Zach starts running two hours later at 4mph and his position can be expressed as:
Z=4(t-2)=4t-8
The distance between Tommy and Zach can be expressed as the hypotenuse length of a right triangle with the distances for Tommy and Zach being the lengths of the sides...
d^2=T^2+Z^2
d^2=(3t)^2+(4t-8)^2
d^2=9t^2+16t^2-64t+64
d^2=25t^2-64t+64, and we want to know when they are 8 miles apart
25t^2-64t+64=8^2
25t^2-64t+64=64
25t^2-64t=0
25t(t-2.56)=0
So 2.56 hours after Tommy started running they will be 8 miles apart.
To be clear though, this is the time Tommy spent running, or the time that elapsed since Tommy started running. Zach has only been running for 0.56 hours. So if they are looking for the time Zach ran it is 0.56 not 2.56 hours.
Answer:
d. The Chi-Square distribution.
Step-by-step explanation:
Hello!
You have one population: Students at ABC University
One study variable: X: College a student is enrolled in, categorized: Bussiness College "B", Liberal Arts College "A" and Education College "E".
The objective of this study is to test if the proportions of students enrolled in each college are different from the known data.
To do this a sample of 300 students was taken and the major they are studying recorded, the observed proportions are to be compared to the expected proportions.
The correct statistic test to use in this case is a Chi-Square Goodness to Fit test.
I hope it helps!
