All categories

3 years ago

The set of points P(0, 3), Q(2, 0), R(4, -3) are collinear and the line has a slope of _____.

Mathematics

2 answers:

vampirchik [111]3 years ago

7 0

Answer:

slope = -1.5

Step-by-step explanation:

A set of three or more points are said to be collinear if they all lie on the same straight line.

We have been given the following collinear set of points;

P(0, 3), Q(2, 0), R(4, -3)

This implies that P, Q, and R lie on the same line.

The slope of a line is defined as; (change in y)/(change in x)

Using the points P and Q, the slope of the line is calculated as;

(0-3)/(2-0) = -3/2 = -1.5

miss Akunina [59]3 years ago

3 0

Answer:

-3/2

Step-by-step explanation:

You might be interested in

Which expression is equivalent to (2^3)^5?

Alenkasestr [34]

<span>(2^3)^5
=2^(3*5)
= 2^15

hope it helps</span>

8 0

3 years ago

Read 2 more answers

Ques

natulia [17]

Answer:

Step-by-step explanation:

In a Pythagorean triple the square on the longest side is equal to the sum of the squares on the other 2 sides.

longest side = 10 ⇒ 10² = 100

6² + 8² = 36 + 64 = 100

A is a Pythagorean triple

longest side = 17 ⇒ 17² = 289

8² + 15² = 64 + 225 = 289

B is a Pythagorean triple

longest side = 9 ⇒ 9² = 81

5² + 8² = 25 + 64 = 89

89 ≠ 81

C is not a Pythagorean triple

longest side = 13 ⇒ 13² = 169

5² + 12² = 25 + 144 = 169

D is a Pythagorean triple

6 0

3 years ago

An extremely large sink hole has opened up in a field just outside of the city limits. It is difficult to measure across the sin

abruzzese [7]

Triangle ABC and triangle DCE are congruent, so line DE = line AB

Use the cosine rule to find angle ACB
$52.2^{2}= 50^{2}+ 70^{2}-(2*50*70*cos(ACB))$
$2724.84=7400-(7000cos(ACB))$
$2724.84-7400=-7000cos(ACB)$
$-4675.16=-7000cos(ACB)$
$\frac{4675.16}{7000}=cos(ACB)$
$Angle ACB= cos^{-1} ( \frac{4675.16}{7000})$
Angle ACB = 48.1°