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3 years ago

What is the interquartile range 53, 62, 67, 71, 83, 94, 102, 105

Mathematics

2 answers:

Leona [35]3 years ago

3 0

I believe it's 36.75

Hope this helped!

zalisa [80]3 years ago

3 0

83 is the answer because I like asked my teAcher rn and she said that's the answer

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The gym has 4 times as many baseballs than basketballs the gym has 25 total balls how many more baseballs than basket balls does

ELEN [110]

Let $b$ be the number of baseball and $k$ be the number of basket ball.

We have the following system:

$\begin{cases}b=4k\\b+k=25\end{cases}$

Substitute the first equation into the second:

$4k+k=25 \iff 5k=25 \iff k=5$

which yields

$b=4k=4\cdot 5 = 20$

So, there are 20 baseballs and 5 basketballs, meaning that there are 15 more baseballs than basketballs.

5 0

2 years ago

6. Two points in the plane, ????(19,4) and ????(19,−6), represent the endpoints of the diameter of a circle.

dusya [7]

Answer:

Radius = 5

center is (19,-1)

$(x-19)^2(y+1)^2= 25$

Step-by-step explanation:

Two points in the plane, (19,4) and (19,−6), represent the endpoints of the diameter of a circle.

Distance between the points is calculated using formula

$d=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(19-19\right)^2+\left(-6-4\right)^2}=10$

diameter = 10

radius = diameter divide by 2

Radius = 5

midpoint is the center of the circle

$\left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)$

$\left(\frac{19+19}{2},\:\frac{-6+4}{2}\right)$

(19,-1)

Equation of the circle

$(x-h)^2(y-k)^2= r^2$

h,k is the center and r is the radius

h=19 and k=-1 , r=5

$(x-19)^2(y+1)^2= 25$

8 0

2 years ago

Help!!!!!!!!!!!!!!!!

valkas [14]

Under box 36x + 9, Drag the following:

A.) 9(4x + 1)
D.) (9 . 4x) + (9 . 1)

Under box 9(4x - 1), Drag the following:
B.) (3 . 12x) - (3 . 3)
C.) 36x - 9

Under box (4 . 9x) + (4 . 2), Drag the following:
E.) 4(9x + 2)
F.) 36x + 8

Hope this helps!

5 0

3 years ago

Solve pls brainliest

luda_lava [24]

Answer:

0÷3= 0

0/5= 0

Step-by-step explanation:

sorry if I did it wrong

4 0

2 years ago

Find equations of the spheres with center(1, −1, 6)that touch the following planes.a) xy-planeb) yz-planec) xz-plane

Misha Larkins [42]

Given :

Center of sphere , C( 1 , -1 , 6 ) .

To Find :

Find equations of the spheres with center (1, −1, 6) that touch the following planes.a) xy-plane b) yz-plane c) xz-plane .

Solution :

Distance of the point from xy-plane is :

d = 6 units .

So , equation of circle with center C and radius 6 units is :

$(x-1)^2+(y-(-1))^2+(z-6)^2=6^2\\\\(x-1)^2+(y+1)^2+(z-6)^2=36$

Distance of point from yz-plane is :

d = 1 unit .

So , equation of circle with center C and radius 1 units is :

$(x-1)^2+(x+1)^2+(z-6)^2=1^2\\\\(x-1)^2+(x+1)^2+(z-6)^2=1$

Distance of point from xz-plane is :

d = 1 unit .

So , equation of circle with center C and radius 1 units is :

$(x-1)^2+(x+1)^2+(z-6)^2=1^2\\\\(x-1)^2+(x+1)^2+(z-6)^2=1$

Hence , this is the required solution .

4 0

2 years ago