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natulia [17]
3 years ago
15

59:26 What is the length of the hypotenuse, x, if (20, 21, x) is a Pythagorean triple? 22 29 41 42

Mathematics
2 answers:
Vikki [24]3 years ago
4 0
If the legs are length a and b and hyptonuse is c then
a²+b²=c²

so
if the legs are 20 and 21 and the hypotnuse is x then
20²+21²=x²
400+441=x²
841=x²
29=x
MAXImum [283]3 years ago
3 0

Answer:  the correct option is (B) 29.

Step-by-step explanation:  We are given to find the length of the hypotenuse x, if (20, 21, x) is a Pythagorean triple.

We know that

in a right-angled triangle, the lengths of the sides (hypotenuse, perpendicular, base) is a Pythagorean triple, where

Hypotenuse^2=Perpendicular^2+base^2.

So,  for the given Pythagorean triple, we have

x^2=20^2+21^2\\\\\Rightarrow x^2=400+441\\\\\Rightarrow x^2=841\\\\\Rightarrow x=\sqrt{841}~~~~~~~~~~~~~~~~~[\textup{taking square root on both sides}]\\\\\Rightarrow x=\pm29.

Since the length of the hypotenuse cannot be negative, so x = 29.

Thus, the length of the hypotenuse, x = 29.

Option (B) is CORRECT.

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How do you solve 5x-2x+6x+40-9+1-x+3x-8+15+7
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Explain your answer, please
Molodets [167]

.1.Scale Factor of Triangle STU to Triangle PQR= 1.5

2.Scale Factor of Trapezoid EFGH to Trapezoid JKLM =2

3. about 90 armadillo

1.Side ST: 15 ÷ Side PQ: 10 = 1.5

2.Side JM: 14 ÷Side EH: 7 = 2

3.843/7=120.428571429

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This rounds to 90 armadillo

Hope this helps :3 ❤

8 0
3 years ago
Read 2 more answers
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