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3 years ago

If you spend $60 per month on a cell phone plan, how much should you budget each week for that

Mathematics

2 answers:

natulia [17]3 years ago

8 0

Answer: $15

There are about 4 weeks in a month, so if you spend $60 per month, you would spend 1/4 of that every week.

60/4= $15

Makovka662 [10]3 years ago

8 0

60/4 is 15

therefore $15 should be set aside each week

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Identify the given quadrilateral Can anyone tell me if these are correct?

Lisa [10]

28 might be a parallelogram

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3 years ago

1) 12 2) 10 3) 8 4) 6

Svetlanka [38]

The answer to this question has to be 8

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3 years ago

1. Solve the equation using the zero-product property. -x(5x – 4) = 0

Oxana [17]

Answer:

x = 0, 4/5

Step-by-step explanation:

The zero-product property states that if the product of a and b is zero, then either a = 0, b = 0, or both terms equal zero

Here our a term is -x and our b term is (5x - 4)
Setting each term equal to zero and solving for x we get
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3 years ago

Find the lowest common denominator. 1/6 and 3/8 The lowest common denominator is

tiny-mole [99]

Answer:

24 as the denominator.

Step-by-step explanation:

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8 goes into 24, 3 times.

7 0

4 years ago

Suppose you do an analysis of the starting salaries of 100 recent Lehman graduates. You find that the average starting salary is

madreJ [45]

Answer:

a) (59180,60820)

b) (59020,60980)

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = $60,000

Standard Deviation, σ = $5,000

Sample size, n = 100

a) 90% critical values

$\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}$

Putting the values, we get,

$z_{critical}\text{ at}~\alpha_{0.10} = 1.64$

$60000 \pm 1.64(\frac{5000}{\sqrt{100}} ) = 60000 \pm 820 = (59180,60820)$

b) 95% critical values

$\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}$

Putting the values, we get,

$z_{critical}\text{ at}~\alpha_{0.05} = 1.96$

$60000 \pm 1.96(\frac{5000}{\sqrt{100}} ) = 60000 \pm 980= (59020,60980)$

5 0

3 years ago