The time taken by the pulse to travel from one support to the other is 0.208 s.
<h3>Given:</h3>
The mass of the cord is m = 0.65 kg.
The distance between the supports is, d = 8.0 m.
The tension in the cord is T = 120 N.
The time taken by the pulse to travel from one support to the other is given as,


Here, v is the linear velocity of a pulse. Its value is,



Then,


Thus, the time taken by the pulse to travel from one support to the other is 0.208 s.
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Answer:

Explanation:
Given that,
Initial angular velocity, 
Final angular speed, 
Angular displacement, 
We need to find the angular acceleration of the tire. We can find it using the third equation of rotational kinematics. So,

So, the angular acceleration of the tire is equal to
.
Answer:
16.405m/s
Explanation:
Given, initial velocity = u = 1.93m/s, acceleration = a = 0.750m/s2, time = t = 19.3s, final velocity = v= ?
Using the first equation of linear motion,
v = u + at
v = 1.93 + 0.750 x 19.3
v = 1.93 + 14.475
v = 16.405m/s