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Burka [1]
4 years ago
6

All of the following events can trigger an adaptive radiation except _____.

Physics
1 answer:
stellarik [79]4 years ago
7 0
The answer would be
A. an unusual event splitting a habitat, such as a severe hurricane 
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The posted speed limit on the road heading from your house to school is45 mi/h, which is about 20 m/s. If you live 8 km (8,000 m
zaharov [31]

Answer:

20.

Explanation:

not. tráfic. is. 20. minuts.

6 0
3 years ago
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A cord of mass 0.65 kg is stretched between two supports 8.0 m apart. If the tension in the cord is 120 N, how long will it take
DedPeter [7]

The time taken by the pulse to travel from one support to the other is 0.208 s.

<h3>Given:</h3>

The mass of the cord is m = 0.65 kg.

The distance between the supports is, d = 8.0 m.

The tension in the cord is T = 120 N.

The time taken by the pulse to travel from one support to the other is given as,

v=\frac{d}{t}

t=\frac{d}{v}

Here, v is the linear velocity of a pulse. Its value is,

v=\sqrt{\frac{T d }{m} }

v=\sqrt{\frac{120 * 8}{0.65} }

v= 38.43 m/s

Then,

t=\frac{8}{38.43}

t=0.208 s

Thus, the time taken by the pulse to travel from one support to the other is 0.208 s.

Learn more about tension here:

brainly.com/question/24994188

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7 0
2 years ago
a tire rolls from rest to an angular velocity of 6 radians per second. the angle it turns through is 12 radians. what is the ang
True [87]

Answer:

\alpha =1.5\ rad/s^2

Explanation:

Given that,

Initial angular velocity, \omega_i=0

Final angular speed, \omega_f=6\ rad/s

Angular displacement, \theta=12\ rad

We need to find the angular acceleration of the tire. We can find it using the third equation of rotational kinematics. So,

\omega_f^2-\omega_i^2=2\alpha \theta\\\\\alpha =\dfrac{\omega_f^2-\omega_i^2}{2\theta}\\\\\alpha =\dfrac{6^2-0^2}{2\times 12}\\\\\alpha =1.5\ rad/s^2

So, the angular acceleration of the tire is equal to 1.5\ rad/s^2.

7 0
3 years ago
What two elements are used with other metals to lower their melting points?
vampirchik [111]

Answer:

C) antimony and bismuth

Explanation:

6 0
3 years ago
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A small boat is moving at a velocity of 1.93 m/s when it is accelerated by a river current perpendicular to the initial directio
olasank [31]

Answer:

16.405m/s

Explanation:

Given, initial velocity = u = 1.93m/s, acceleration = a = 0.750m/s2, time = t = 19.3s, final velocity = v= ?

Using the first equation of linear motion,

v = u + at

v = 1.93 + 0.750 x 19.3

v = 1.93 + 14.475

v = 16.405m/s

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3 years ago
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