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2 years ago

8

if ur riding a bike uphill do you want the output force to be greater than the input force or does the output force have to be l

ess than the input?

1 answer:

andrey2020 [161]2 years ago

8 0

Answer: you want your input force harder

Explanation:

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How might burning fossil fuels affect the composition of gases in the atmosphere?

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No "might<span>". The amount of CO2 in the </span>atmosphere<span> HAS gone up since the start of industrialisation as the result of </span>burning fossil fuels<span>.</span>

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2 years ago

If the dartboard below is used to model an atom, which subatomic particles would be located at Z? *

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2 years ago

A student uses a spring loaded launcher to launch a marble vertically in the air. The mass of the marble is

GarryVolchara [31]

Answer:

Part a)

When spring compressed by 2 cm

H = 1.47 m

Part b)

When spring is compressed by 4 cm

H = 5.94 m

Explanation:

Part a)

As we know that the spring is compressed and released

so here spring potential energy is converted into gravitational potential energy at its maximum height

So we will have

$\frac{1}{2}kx^2 = mg(H + x)$

$0.5(220)(0.02)^2 = 0.003(9.81)(H + 0.02)$

so we have

$H = 1.47 m$

Part b)

Similarly when spring is compressed by 4 cm

then we have

$\frac{1}{2}kx^2 = mg(H + x)$

$0.5(220)(0.04)^2 = 0.003(9.81)(H + 0.04)$

so we have

$H = 5.94 m$

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2 years ago

Can someone help me out?

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Answer:

B). Rarefaction :) _____

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2 years ago

Read 2 more answers

What is the initial velocity of a go-kart traveling at a uniform acceleration of 0.5 m/s^2 for 5s as it slows down to a stop?

Arlecino [84]

The go-kart's velocity $v$ after time $t$ is given by

$v=v_0+at$

where $v_0$ is its initial velocity and $a$ is its acceleration. After $t=5\,\mathrm s$ , the go-kart stops completely, so

$0\,\dfrac{\mathrm m}{\mathrm s}=v_0+\left(-0.5\,\dfrac{\mathrm m}{\mathrm s^2}\right)(5\,\mathrm s)\implies v_0=2.5\,\dfrac{\mathrm m}{\mathrm s}$

where $a$ because we know the go-kart is slowing down.

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2 years ago