Answer:
0.0208<p<0.0592
Step-by-step explanation:
-Given the sample size is 400 and the desired proportion is 16.
-The confidence interval can be determined as follows:
#We the use this proportion to find the CI at 95%:
![CI=0.04\pm 1.96\times \sqrt{\frac{0.04(1-0.04)}{400}}\\\\=0.04\pm 0.0192\\\\=[0.0208,0.0592]](https://tex.z-dn.net/?f=CI%3D0.04%5Cpm%201.96%5Ctimes%20%5Csqrt%7B%5Cfrac%7B0.04%281-0.04%29%7D%7B400%7D%7D%5C%5C%5C%5C%3D0.04%5Cpm%200.0192%5C%5C%5C%5C%3D%5B0.0208%2C0.0592%5D)
Hence, the 95% confidence interval is 0.0208<p<0.0592
To find the relation between them, you need transform them to the same currency. Let's transform them to cents.
$3.60 = 360 cents.
One quarter is 25 cents, and one nickel is 5 cents.
So 360 = 25q + 5n
Hope this helps! :D
Answer:
y=-2/3x-3
Explanation
U = - 4 i + 1 j
v = 4 i + 1 j
| u | = √ (-4)² + 1² = √ 17
| v | = √4² + 1² = √ 17
| u + v | = √(u + v)²=
= √( u² + 2 u v + v² )= ...
cos ( u, v ) = (-16+1) / (|u| |v|) = -15/17
...= √(17 + 2 · √17 · √17 · ( -15/17) +17) =
= √ 34 - 30 = √ 4 = 2
Answer: C ) 2
