Given side length "a" and angle "A", calculate the diagonals<span><span>
p = square root [( 2a^2 - 2a^2 cos(A) )]
</span>q = </span><span>square root [( 2a^2+ 2a^2 cos(A) )]</span>
http://www.calculatorsoup.com/calculators/geometry-plane/rhombus.php
side = 36
cos (32) = 0.84805
p = <span>small diagonal = </span>
<span>
<span>
<span>
19.8457652914
</span>
</span>
</span>
<span><span>
</span>
</span>
q =
large diagonal =
<span>
<span>
<span>
69.2108777578
</span>
</span>
</span>
Answer:
Step-by-step explanation:
Since we use the sides opposite and adjacent to the given angle, we will use the tangent ratio:
Insert the given values:
Since we need to find the angle, use the inverse:
Insert the equation into a calculator:
Round to the nearest tenth:
:Done
Y= 3/8+2
This is the answer because in the equation 8y-3x+16 you would re-write it as 8y=3x+16 but to write it in slope-intercept form, you need to get the 8 away from the y. To do this you divide y by everything; creating y=3/8x+2 ( slope intercept form).
Answer:
is this even a question
Step-by-step explanation:
