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4 years ago

What is the measure of 2 G?

Mathematics

1 answer:

patriot [66]4 years ago

7 0

Answer:

28 =<G

Step-by-step explanation:

This is an isosceles triangle, so angle E and angle G must be the same.

<E = <G

28 =<G

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Mrs. Reynold’s sprinkle system has 9 stations that water all the parts of her front and back lawn. Each station runs for an equa

NeTakaya

Answer:

108 minutes

Step-by-step explanation:

48/4= 12 minutes per 1 station

9x12=108 minutes

4 0

3 years ago

What is 350÷10³= I need it for class

natali 33 [55]

Answer:

0.35

Step-by-step explanation:

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3 years ago

What is the present value of a fund that earns 15% on its balance each year, from which $10,000 must be paid a year for 6 years,

Masteriza [31]

Answer:

The present value of the fund=$25,939.66

Step-by-step explanation:

Step 1

Determine the future value of the fund as shown;

Future value(F.V)=payment amounts per year×number of years

where;

payment amounts per year=$10,000

number of years=6

replacing;

Future value (F.V)=(10,000×6)=60,000

Future value (F.V)=$60,000

Step 2

Determine the present value (P.V) of the fund as shown;

F.V=P.V(1+r)^n

where;

F.V=future value

P.V=present value

r=annual interest rate

n=number of years

In our case;

F.V=$60,000

P.V=unknown

r=15%=15/100=0.15

n=6

replacing;

60,000=P.V(1+0.15)^6

60,000=P.V(1.15)^6

P.V=60,000/{(1.15)^6}

P.V=25,939.66

The present value of the fund=$25,939.66

3 0

3 years ago

Find the variance of the following data. Round your answer to one decimal place. x 1 2 3 4 5 P(X=x) 0.3 0.2 0.2 0.1 0.2

Reptile [31]

The variance of a distribution is the square of the standard deviation

The variance of the data is 2.2

<h3>How to calculate the variance</h3>

Start by calculating the expected value using:

$E(x) = \sum x* P(x)$

So, we have:

$E(x) = 1 * 0.3 + 2* 0.2 +3 * 0.2 + 4 * 0.1 + 5 * 0.2$

This gives

$E(x) = 2.7$

Next, calculate E(x^2) using:

$E(x^2) = \sum x^2* P(x)$

So, we have:

$E(x^2) = 1^2 * 0.3 + 2^2* 0.2 +3^2 * 0.2 + 4^2 * 0.1 + 5^2 * 0.2$

$E(x^2) = 9.5$

The variance is then calculated as:

$Var(x) = E(x^2) - (E(x))^2$

So, we have:

$Var(x) = 9.5 - 2.7^2$

$Var(x) = 2.21$

Approximate

$Var(x) = 2.2$

Hence, the variance of the data is 2.2