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dem82 [27]
2 years ago
15

You want to purchase a motorcycle 4 years from now, and you plan to save $3,500 per year, beginning immediately. You will make 4

deposits in an account that pays 5.7% interest. Under these assumptions, how much will you have 4 years from today?
a.$16,112
b.$16,918
c.$17,763
d.$18,652
e.$19,584
Business
1 answer:
neonofarm [45]2 years ago
8 0

Answer:

The answer is option a). $16,111.99

Explanation:

To calculate the total amount amount you will have after 4 years, we need to sum the total amount after the end of each year for four years.

a). Total amount at the end of the first year

Total amount=Deposit+Interest

where;

Deposit=$3,500

Interest=Deposit×interest rate×number of years=3,500×(5.7/100)×1=199.5

replacing;

Total amount after the end of the first year=(3,500+199.50)=$3,699.50

b). Total amount at the end of the second year

Deposit for the second year=Total amount after end of first year+3,500

Deposit for the second year=(3,699.50+3,500)=7,199.50

Total amount at the end of the second year=Deposit+Interest

Total amount at the end of the second year=7,199.50+(7,199.50×5.7/100×1)=7,609.8715

Total amount after the end second year=$7,609.8715

c). Total amount at end of the third year

Deposit for the third year=Total amount after end of second year+3,500

Deposit for the third year=(7,609.8715+3,500)=11,109.8715

Total amount at the end of the third year=Deposit+Interest

Total amount at the end of the third year=11,109.8715+(11,109.8715×5.7/100×1)=11,743.134

Total amount for the end of the third year=$11,743.134

d). Total amount at end of fourth year

Deposit for the fourth year=Total amount at the end of the second year+3,500

Deposit for the fourth year=(11,743.134+3,500)=15,243.134

Total amount at the end of the fourth year=Deposit+Interest

Total amount at the end of the third year=15,243.134+(15,243.134×5.7/100×1)=16,111.99

Total amount for the end of the fourth year=$16,111.99

4 years from now, you will have $16,111.99

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Statement (b)

Revenue is recognized and with that retained earnings will increase, and accordingly stockholder's equity will also increase by $5,200,

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Statement (c)

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Statement (d)

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Assuming the Coase theorem applies, an efficient allocation of a resource will result ... A. only if the government acts to inte
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Answer:

B. through negotiations between the parties involved.

Explanation:

  • correct answer is through negotiations between the parties involved because According to Coase theory, priority rights are best defined by negotiation between the parties involved and there is no transaction cost in negotiations.                            
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A corporation has $7,000,000 in income after paying preferred dividends of $500,000. The company has 1,000,000 shares of common
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Answer:

Price earning ratio= 8  times

Explanation:

Price earning ratio = Price per share /Earnings per share

Price per share = 56, EPS =?

Price per share =56, EPS = Total earnings available to ordinary shareholders/Number of shares

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Price earning ratio = 56/7= 8  times

Price earning ratio= 8  times

                         

8 0
3 years ago
The cob Douglas production function is given by Q(K,L)=AK^1.4*L^1.6
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Part a) The Cob Douglas production function is given as:

Q(K,L)=AK^{1.4} L^ {1.6 } .

To show that this function is homogeneous with degree 3, we introduce be a parameter, t.

Q(tK,tL)=A(tK)^{1.4} (tL)^ {1.6 } .

Using properties of exponents, we on tinder:

Q(tK,tL)=At^{1.4}K^{1.4} t^ {1.6 }L^ {1.6 } .

This implies that:

Q(tK,tL)=t^{1.4} \times t^ {1.6 }(AK^{1.4} L^ {1.6 } )

Q(tK,tL)=t^{1.4 + 1.6}(AK^{1.4} L^ {1.6 } )

Simplify the exponent of t to get;

Q(tK,tL)=t^{3}(AK^{1.4} L^ {1.6 } )

Hence the function is homogeneous with degree, 3

Part b) To verify Euler's Theorem, we must show that:

K\frac{\partial Q}{\partial \: K}+L\frac{\partial Q}{\partial \: L}=3AK^{1.4}L^{1.6}

Verifying from the left:

K\frac{\partial Q}{\partial \: K}+L\frac{\partial Q}{\partial \: L} =K(1.4AK^{0.4} L^{1.6}) + L(1.6AK^{1.4} L^{0.6})

K\frac{\partial Q}{\partial \: K}+L\frac{\partial Q}{\partial \: L} =1.4(AK^{1.4} L^{1.6}) + 1.6(AK^{1.4} L^{1.6})

K\frac{\partial Q}{\partial \: K}+L\frac{\partial Q}{\partial \: L} =(1.4 +  1.6)(AK^{1.4} L^{1.6})

K\frac{\partial Q}{\partial \: K}+L\frac{\partial Q}{\partial \: L} =3(AK^{1.4} L^{1.6})

Q•E•D

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