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2 years ago

A 360LB gorilla climbs a tree to a height of 20ft. Find the work done if the gorilla reaches that height in:

2 answers:

7 0

The problem ask to find the work done of the gorilla reaches that height of 20 ft in 10s and 5s if the gorilla has a mass of 360lb. So base on that data allow, you can solve the work by multiplying the force and the distance, and force is calculated by multiplying mass and acceleration and acceleration is calculated by velocity over time. So the answer would be that force is 7200 N

Trava [24]2 years ago

6 0

Answer:

For both options a and b the work done is 7200 ft lb.

Step-by-step explanation:

Given : A 360 LB gorilla climbs a tree to a height of 20 ft.

To Find : The work done if the gorilla reaches that height in a) 10 seconds b) 5 seconds ?

Solution :

Work done is defined as the change in the energy of the gorilla must equal the net work done by the gorilla in climbing.

We have given,

Weight = 360 LB and height = 20 ft.

The work done is defined as

$W=\int\limits^{20}_{0} {360} \, dx$

$W=[360x]^{20}_{0}$

$W=360(20)-360(0)$

$W=7200ft\ lb$

Therefore, For both options a and b the work done is 7200 ft lb.

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On Monday, Noah finds 19 big grasshoppers and 9 small ones in his garden. What is the experimental probability of finding a smal

Lina20 [59]

That would be 9 /(19+9) = 9/28 Answer

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3 years ago

Read 2 more answers

An English professor assigns letter grades on a test according to the following scheme. A: Top 9% of scores B: Scores below the

sergeinik [125]

Answer:

The minimum score required for an A grade is 83.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 72.3 and a standard deviation of 8.

This means that $\mu = 72.3, \sigma = 8$

Find the minimum score required for an A grade.

This is the 100 - 9 = 91th percentile, which is X when Z has a pvalue of 0.91, so X when Z = 1.34.

$Z = \frac{X - \mu}{\sigma}$

$1.34 = \frac{X - 72.3}{8}$

$X - 72.3 = 1.34*8$

$X = 83$

The minimum score required for an A grade is 83.

5 0

2 years ago

For the given function f and g, complete parts (a)-(h). For parts (a)-(d), also find the domain.

kakasveta [241]

Answer:

a) (f + g)(x) = 9x + 1

Domain: x ε R

b) (f - g)(x) = (-5x + 13)

Domain: x ε R

c) (f.g)(x) = 14x² + 37x - 42

Domain: x ε R

d) (f/g)(x) = (2x + 7)/(7x -6)

Domain: (x ε R except x = 6/7)

e) (f + g)(7) = 64

f) (f - g)(2) = 3

g) (f.g)(3) = 195

h) (f/g)(x) = 1/3

Step-by-step explanation:

f(x) = 2x + 7, g(x) = 7x - 6

a) (f + g)(x) = f(x) + g(x) = (2x + 7) + (7x - 6)

(f + g)(x) = 9x + 1

Since x is defined for functions f & g for all real numbers, the domain of (f + g)(x) is x ε R

b) (f - g)(x) = f(x) - g(x) = (2x + 7) - (7x - 6)

(f - g)(x) = (-5x + 13)

Since x is defined for functions f & g for all real numbers, the domain of (f - g)(x) is x ε R

c) (f.g)(x) = f(x) × g(x) = (2x + 7)(7x - 6)

(f.g)(x) = 14x² - 12x + 49x - 42 = 14x² + 37x - 42

Since x is defined for functions f & g for all real numbers, the domain of (f.g)(x) is x ε R

d) (f/g)(x) = f(x)/g(x) = (2x + 7)/(7x -6)

x is defined for functions f & g for all real numbers, the domain of (f/g)(x) will be x ε R except when the denominator vanishes (that is, goes to zero). This will cause the function to take up values of ∞.

This will happen when 7x - 6 = 0, x = 6/7.

Therefore, the domain of (f/g)(x) is x ε R except the point, x = 6/7.

e) (f + g)(7) = 9(7) + 1 = 64

f) (f - g)(2) = -5(2) + 13 = 3

g) (f.g)(3) = 14(3²) + 37(3) - 42 = 195

h) (f/g)(27) = (2(27) + 7)/(7(27) - 6) = 61/183 = 1/3

Hope this Helps!!!

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2 years ago

Without calculating, which has a bigger volume. A cube that has a length, width, and height of 18 m. Or a sphere with a radius o

Evgesh-ka [11]

Weird. A period appears above this... huh.

Answer:

[Th]e cube has a greater value.

Step-by-step explanation:

What the word problem really wants us to get [is ]the question of 'Which is greater, A=6a^2 when 'a' [is] 18 or A=4 $\pi$ r^2 when r = 9? And here's how to solve that.

Starting with the[ c]ube we have A=6a^2. A bit t[o]o simple, right?

A=6(18)^2 Substitute numbers.

A=6(324) Solve ex[p]onents.

A=1944 Mult[i]ply.

So w[e] know that the cube is 1944 meters cube[d ] in area. But what about the more [f]ormidable sphere? Fo[r] it we need a slightly m[o]re co[m]plicated formula, A=4 $\pi$ r^2. However, instead of using the real pi I will be rounding to 3.14, since we have no calculator so anything more would take way too long and fry your[ bra]in.

A=4(3.14)(9)^2 Subst[i]tute numbers.

A=4(3.14)(81) Solve expone[n]ts.

A=12.56(81) Multip[ly].

A=1017.36 Multiply again[.]

Now, since I'm sure all of us can count, we know that 1944 is greater than 1017.36. Or in other words, the cube is bigger than the sphere.

And PLEASE don't copy this guys. Make your own iteration. Change it up!

3 0

2 years ago

A tour company has a boat that sits at most 40 passengers. For a cruise on the Hudson River they charge $12 per adult and $5 per

EleoNora [17]

Answer:

Step-by-step explanation:

For the adults:

$12 times the 14 adults which is: $168

Then for the kids:

$5 times the 9 kids which is: $45

Add next:

$168 plus the $45 equals $213

A(14)+b(5)=c

5 0

2 years ago