Answer:
I don’t know about the last part but what I do know id the answer to the equation.
Answer: 1 1/3
Step-by-step explanation:
1. Remove the paranthesis
Removing the paranthesis will make it much easier to solve the equation.
We now have 4 1/6 + -2 5/6.
2. Rearrange the equation
We can’t have two symbols next to each other. We need to cross out one symbol so we can have only one. + and - = -. So let’s keep the "-" symbol.
We now have 4 1/6 - 2 5/6.
3. Solve the remaining equation
Now that we have a proper equation which we can solve, let’s do it.
We should then end up with 1 1/3.
Answer: 1 1/3
Celia bought a bag of 12 goldfish for $3 dollar.
- Cost of 12 goldfish = $3
- Cost of 1 goldfish = $3/12 = $1/4
= $0.25
<h3><em>The </em><em>cost </em><em>of </em><em>1</em><em> </em><em>goldfish </em><em>is </em><em>$</em><em>0</em><em>.</em><em>2</em><em>5</em><em>.</em></h3>
Answer:
remember the chain rule:
h(x) = f(g(x))
h'(x) = f'(g(x))*g'(x)
or:
dh/dx = (df/dg)*(dg/dx)
we know that:
z = 4*e^x*ln(y)
where:
y = u*sin(v)
x = ln(u*cos(v))
We want to find:
dz/du
because y and x are functions of u, we can write this as:
dz/du = (dz/dx)*(dx/du) + (dz/dy)*(dy/du)
where:
(dz/dx) = 4*e^x*ln(y)
(dz/dy) = 4*e^x*(1/y)
(dx/du) = 1/(u*cos(v))*cos(v) = 1/u
(dy/du) = sin(v)
Replacing all of these we get:
dz/du = (4*e^x*ln(y))*( 1/u) + 4*e^x*(1/y)*sin(v)
= 4*e^x*( ln(y)/u + sin(v)/y)
replacing x and y we get:
dz/du = 4*e^(ln (u cos v))*( ln(u sin v)/u + sin(v)/(u*sin(v))
dz/du = 4*(u*cos(v))*(ln(u*sin(v))/u + 1/u)
Now let's do the same for dz/dv
dz/dv = (dz/dx)*(dx/dv) + (dz/dy)*(dy/dv)
where:
(dz/dx) = 4*e^x*ln(y)
(dz/dy) = 4*e^x*(1/y)
(dx/dv) = 1/(cos(v))*-sin(v) = -tan(v)
(dy/dv) = u*cos(v)
then:
dz/dv = 4*e^x*[ -ln(y)*tan(v) + u*cos(v)/y]
replacing the values of x and y we get:
dz/dv = 4*e^(ln(u*cos(v)))*[ -ln(u*sin(v))*tan(v) + u*cos(v)/(u*sin(v))]
dz/dv = 4*(u*cos(v))*[ -ln(u*sin(v))*tan(v) + 1/tan(v)]
Answer:
13y-10
Step-by-step explanation:
Expand: -5(-y+2): 5y-10
Add similiar elements: 8y+5y=13y
=13y-10
