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amid [387]
4 years ago
14

X^2+13x-30 find the vertex

Mathematics
1 answer:
ra1l [238]4 years ago
6 0

Answer:

(−13/2,−289/4)

Step-by-step explanation:

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A consistent dependent system of equations is a system with
ValentinkaMS [17]

Answer:

Systems of equations can be classified by the number of solutions. , . , . If a consistent system has an infinite number of solutions, it is dependent.

5 0
3 years ago
Willow Brook National Bank operates a drive-up teller window that allows customers to complete bank transactions without getting
slega [8]

Answer:

(a) <em>λ</em> = 2.

(b) P (X = 0) = 0.1353; P (X = 1) = 0.2706;

    P (X = 2) = 0.2706; P (X = 3) = 0.1804

(c) P (Delay Problems) = 0.1431.

Step-by-step explanation:

Let <em>X</em> = number of arrivals at the drive-up teller window.

The average number of arrivals at the drive-up teller window per minute is,

<em>p</em> = 0.4 customers/ minute.

(1)

Compute the expected number of customers at the drive-up teller window in <em>n</em> = 5 minutes as follows:

E(X)=\lambda\\=np\\=5\times 0.4\\=2

Thus, the mean number of customers that will arrive in a five-minute period is <em>λ</em> = 2.

(2)

The random variable <em>X</em> follows a Poisson distribution with parameter λ = 2.

The probability mass function of <em>X</em> is:

P(X=x)=\frac{e^{-2}2^{x}}{x!};\ x=0,1,2,3...

Compute the probability of exactly 0 arrivals in 5 minutes as follows:

P(X=0)=\frac{e^{-2}2^{0}}{0!}=\frac{0.1353\times 1}{1}=0.1353

Compute the probability of exactly 1 arrivals in 5 minutes as follows:

P(X=1)=\frac{e^{-2}2^{1}}{1!}=\frac{0.1353\times 2}{1}=0.2706

Compute the probability of exactly 2 arrivals in 5 minutes as follows:

P(X=2)=\frac{e^{-2}2^{2}}{2!}=\frac{0.1353\times 4}{2}=0.2706

Compute the probability of exactly 3 arrivals in 5 minutes as follows:

P(X=3)=\frac{e^{-2}2^{3}}{3!}=\frac{0.1353\times 8}{6}=0.1804

Thus, the values are:

P (X = 0) = 0.1353

P (X = 1) = 0.2706

P (X = 2) = 0.2706

P (X = 3) = 0.1804

(3)

Delays occur in the service time if there are more than three customers arrive during any five-minute period.

Compute the probability that there are more than 3 customers as follows:

P (X > 3) = 1 - P (X ≤ 3)

              =1-\sum\limits^{3}_{x=0}{\frac{e^{-2}2^{x}}{x!}}\\=1-(0.1353+0.2706+0.2706+0.1804)\\=1-0.8569\\=0.1431

Thus, the probability that delays will occur is 0.1431.

3 0
4 years ago
Doing some more so please help
ohaa [14]

The second one just had this yesterday

6 0
3 years ago
Read 2 more answers
Which is bigger, 40% of 120 or 1/4 of 200
Veseljchak [2.6K]


40% = 0.4 * 120= 48

200/4 = 50

1/4 of 200 is bigger.

8 0
3 years ago
The poInt (-3,2) is on the line given by which equation
sergejj [24]
There are an infinite amount of equations that pass through a single point. You must provide the slope or y-intercept to get a single equation. 

Hope that clarifies. 
8 0
3 years ago
Read 2 more answers
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