2 years ago

Whats up you mofos good morning

Mathematics

1 answer:

Paul [167]2 years ago

6 0

yap mofos morning good

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What is 2x+y=12 and 3x-18=y which are linear equations but need to be solved by elimination

Sidana [21]

Answer:

x=6,y=0

Step-by-step explanation:

2x+y=12

3x-y=18

5x=30

x=6

6(3)-y=18

18-y=18

y=0

8 0

3 years ago

It can be multiple answers and explain how to figure this out

Leno4ka [110]

None of the two answer choices are correct, answer is none of the above

simplify by multiplying by 2 we get 10g+6h+8. neither of the two choices match

7 0

3 years ago

What’s the answer to this if u know tho! Thank uuu :)))

alukav5142 [94]

Answer:

180=40+(x+20)

x+20=140

x=120

6 0

3 years ago

Read 2 more answers

Find the length of the curve y = integral from 1 to x of sqrt(t^3-1)

Arlecino [84]

$y=\displaystyle\int_1^x\sqrt{t^3-1}\,\mathrm dt$

By the fundamental theorem of calculus,

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm d}{\mathrm dx}\displaystyle\int_1^x\sqrt{t^3-1}\,\mathrm dt=\sqrt{x^3-1}$

Now the arc length over an arbitrary interval $(a,b)$ is

$\displaystyle\int_a^b\sqrt{1+\left(\frac{\mathrm dy}{\mathrm dx}\right)^2}\,\mathrm dx=\int_a^b\sqrt{1+x^3-1}\,\mathrm dx=\int_a^bx^{3/2}\,\mathrm dx$

But before we compute the integral, first we need to make sure the integrand exists over it. $x^{3/2}$ is undefined if $x$ , so we assume $a\ge0$ and for convenience that $a$ . Then

$\displaystyle\int_a^bx^{3/2}\,\mathrm dx=\frac25x^{5/2}\bigg|_{x=a}^{x=b}=\frac25\left(b^{5/2}-a^{5/2}\right)$

6 0

3 years ago

Simplify (2a+5)6a^2<br> Can someone help please

Wewaii [24]

Answer:

12a^3+30a^2

Step-by-step explanation:

6a^2(2a+5)

12a^3+30a^2

5 0

3 years ago