Whats up you mofos good morning

Please help with 6 and 7

Maru [420]

Answer:

6a) i- 2hrs 36mins ii- 3hrs 12mins

b) car A≈ 76.9km/h car B≈ 62.5km/h

c)------

7a) 35km

b) car A=75km car B=60km

c) 30km

d) car A≈36mins car B≈48mins

Step-by-step explanation:

6a) Using the graph follow the lines until they finish then go downwards until you get to the x-axis. The x-axis is going up by 12mins for each square.

b) Using the answer from a, you divide 200km by the time.

For car A 2hrs 36mins becomes 2.6 because 36mins/60mins=0.6

∴ car A: 200/2.6≈ 76.92km/h

For car B 3hrs 12mins becomes 3.2 because 12mins/60mins=0.2

∴ car B: 200/3.2≈ 62.5km/h

7a) Using the graph go down from where the line of car A finished to meet car B. The y-axis is going up by 5km for each square.

b) Starting from the x-axis at 1 hour go upwards to see where you meet the car B line (60km) and car A line(75km). (sorry if that does not really make sense).

c) Difference from car A line to car B:

155km-125km=30km

d) Going across from 50km meet car A line and go down to see it has been travelling for approx. 36mins. Then continue across to car B line, go down to see it reached 50km at approx. 48mins.

Hope this helps.

5 0

3 years ago

A ball is thrown from an initial height of 1 meter with an initial upward velocity of 15m/s. The ball's height h (in meters) aft

lakkis [162]

$\bf \stackrel{\textit{ball's height}~\hfill }{\stackrel{\downarrow }{h}=1+15t-5t^2}\implies \stackrel{\textit{ball's height}~\hfill }{\stackrel{\downarrow }{6}=1+15t-5t^2}\implies 0=-5+15t-5t^2 \\\\\\ ~~~~~~~~~~~~\textit{using the quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{5}t^2\stackrel{\stackrel{b}{\downarrow }}{-15}t\stackrel{\stackrel{c}{\downarrow }}{+5}=0 \qquad \qquad t= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}$

$\bf t=\cfrac{-(-15)\pm\sqrt{(-15)^2-4(5)(5)}}{2(5)}\implies t=\cfrac{15\pm\sqrt{225-100}}{10} \\\\\\ t=\cfrac{15\pm\sqrt{125}}{10}\implies t=\cfrac{15\pm\sqrt{5^2 \cdot 5}}{10}\implies t=\cfrac{\stackrel{3}{~~\begin{matrix} 15 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\pm ~~\begin{matrix} 5 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~\sqrt{5}}{\underset{2}{~~\begin{matrix} 10 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}$

$\bf t=\cfrac{3\pm \sqrt{5}}{2}\implies t= \begin{cases} \frac{3+ \sqrt{5}}{2} \approx 2.618\\\\ \frac{3- \sqrt{5}}{2}\approx 0.382 \end{cases}$

8 0

2 years ago

granola bite contains 27 calories. Most of the calories come from grams of carbohydrates. The rest come from other ingredients.

azamat

Answer:

5 1/2

Step-by-step explanation:

The calories contained are from grams of carbohydrates and other ingredients

One gram of carbohydrate contains 4 calories

The equation 4c + 5 = 27 represents the relationship between these quantities.

1. 5 from the equation represent calories from other ingredients

2. Neither 8 nor 3 is the solution to the equation

4c + 5 = 27

When 8 is the solution

4(8)+5=27

32+5=27

37=27

When 3 is the solution

4(3)+5=27

12+5=27

17=27

Neither 8 nor 3 is the solution to the equation because 8 gives a higher calories in the granola bite and 3 gives a lower calories in the granola bite.

3. Solution to the equation

4c + 5 = 27

4c= 27-5

4c = 22

Divide both sides by 4

c=22/4

=5 2/4

=5 1/2

The solution to the equation is 5 1/2

7 0

3 years ago

Which expression shows how to find the quotient of 4.8÷2?

xenn [34]

Answer:

[A] (4 ÷ 2)+(0.8 ÷ 2)

Step-by-step explanation:

Divide the 2 into each digit, which must be in the same spot it was before:

Knowing that 8 in 4.8 ⇒ 0.8

Thus, you can infer that [B] is wrong

You also infer that [D] and [C] is wrong because 4 is a whole number.

Thus, that left us with [A] 4 ÷ 2+0.8 ÷ 2 which shows the quotient of 4.8 ÷ 2

Hence, [A] 4 ÷ 2+0.8 ÷ 2 is the answer.

<em>~Learn with Lenvy~</em>

5 0

2 years ago

Read 2 more answers

What is 7/8 plus 1/3

horsena [70]

7/8 +1/3 =1 1/8 that is the answer

5 0

3 years ago