Answer:
The correct answer would be:
- Genotype ratio: 1 (PP) : 2 (Pp) : 1 (pp)
- Phenotypic ratio: 3 (polka-dot tails) : solid colored tail
The genotype of both parents is Pp (heterozygous).
Thus, both the parent would produce two types of gametes which are P and p.
The cross would result in the production of offspring with three types of genotype PP, Pp, and pp in 1:2:1.
Offspring with PP and Pp will have a polka-dotted tail as it is the dominant trait.
Thus, the phenotype ratio would be 3 (polka-dotted tail) : 1 (solid colored tail).
Answer:
1128.
Explanation:
The dominant taster phenotype is 1482.
The recessive taster phenotype = 2400 – 1482 = 918
.
Recessive phenotypes = 2400 – 1482 = 918
The recessive phenotype frequency = q² = 918 / 2400 = 0.38.
the recessive allele frequency q = √0.38 = 0.62.
The dominant allele frequency, p = 1-q = 1- 0.62 = 0.38
The heterozygous frequency = 2pq = 2 ×0.38 × 0.62 = 0.47
.
The heterozygous individual in the population = 0.47 × 2400 = 1128.
Thus, the answer is 1128.