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3 years ago

When a car is parked in hot sunlight, the temperature of the car’s seats and the thermal energy of the seats .

Biology

2 answers:

Ad libitum [116K]3 years ago

6 0

Answer:

first one should be increase second one should be increase also

Explanation:

Helen [10]3 years ago

3 0

The temperature of the cars seats and the thermal energy of the seats INCREASES.

Sunlight can trasfer heat energy by radiation, when heat is transfered, the seats gain heat and the temperature rises due to the increase of kinetic energy of the molecules, the molecules move faster. As the temperature rises, the thermal energy is increased too because kinetic energy (and potential, but this is about the state of matter) of the molecules makes up the thermal energy of an object.

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Each of the four pedigrees that follow represents a human family within which a genetic disease is segregating. Affected individ

Ne4ueva [31]

Answer:

The following four traits are -:

Pedigree 1 - A recessive trait (autosomal recessive) is expressed by pedigree 1.
Pedigree 2- Recessive inheritance is defined by Pedigree 2.
Pedigree 3 - The inheritance of the dominant trait (autosomal dominant) is illustrated by Pedigree 3.
Pedigree 4- An X-like dominant trait is expressed by Pedigree 4.

Explanation:

Explaination of each pedigree chart-

Pedigree 1 demonstrates the recessive trait since their children have been affected by two unaffected individuals. If the characteristics were X-linked, in order to have an affected daughter, I-1 would have to be affected. $X^A$ In this, both parents are autosomal recessive trait carriers, so the child will be affected by a 1/4 (aa)
Recessive inheritance is defined by Pedigree 2. This is X-related inheritance as autosomal recessive inheritance has already been accounted for in part 1. This inference is confirmed by evidence showing that the father (I-1) is unaffected and that only the sons exhibit the characteristic in generation II, suggesting that the mother must be the carrier. The individual I-2 is a carrier for this X-linked trait. A typical Xa chromosome is attached to the unaffected father (I-1), so the chance of carrier II-5 is 1/2. Probability of an affected son = 1/2 (probability II-5 is a carrier) x 1/2 (probability II -5 contributes ( $X^A$ ) x 1/2 (probability of Y from father II-6) = 1/8. An affected daughter's likelihood is 0 because a typical $X^A$ must be contributed by II-6.
The inheritance of the dominant trait is demonstrated by Pedigree 3 because affected children still have affected parents (remember that all four diseases are rare). The trait must be autosomal dominant because it is passed down to the son by the affected father. There is a 1/2 risk that the heterozygous mother (II-5) would pass on mutant alleles to a child of either sex for an autosomal dominant feature.
Pedigree 4 is an X-linked dominant function characterized by the transmission to all of his daughters from the affected father but none of his son. On the mutant X chromosome, the father (I-1) passes on to all his daughters and none of his sons. As seen by his normal phenotype, II-6 therefore does not bear the mutation. An affected child's likelihood is 0.

In the question the pedigree chart was missing ,hence it is given below.

7 0

3 years ago

Which of the following choices would be the most logical third step in Connell's experimental procedure, permitting him to eithe

gizmo_the_mogwai [7]

Answer: B) The experimental group tests to see if the presence of Balanus in some manner prevents Chthamalus from growing.

Explanation:

The most logical third step in Connell's experimental procedure, permitting him to either accept or reject his hypothesis of competitive exclusion is the experimental group tests to see if the presence of Balanus in some manner prevents Chthamalus from growing.

Balanus is a species of crustacean, as know as sea acorns, whereas Chthamalus is a species of barnacles that can easily be found in the northern hemisphere's coasts.

8 0

3 years ago

Help me do this graph please!! Due: Thursday 12th March 50 Points

Alecsey [184]

Removes carbon from air: photosynthesis by plants and algae
Release of carbon into atmosphere: respiration (animals exhale CO2), factory emissions, eruption of volcanoes, hydrothermal vents, and breakdown of organic matter
Release of carbon into the soil: Shells of marine organisms form limestone, and some carbon from decomposing organisms is stored in the soil
*This isn’t every possible pathway but hopefully this will help get you started. I’m going to attach a picture of the carbon cycle (not mine) to help you visualize the process.

4 0

3 years ago

the flounders ability to camouflage itself in different environments is a characteristic of Life known as

xxMikexx [17]

The answer is iguana because they are the only animal that changes color

3 0

3 years ago

Read 2 more answers

Can somebody give me the answer for these...

labwork [276]

Answer:

1. Life cycle of a cell starts from

G1 phase - S phase (synthesise phase) - G2 phase - mitosis.

2. By mitosis bcoz it restore nucleo cytoplasmic ratio means ploidy of cell remain same.

3. Bcoz of transformation of normal cells into cancerous cells by Carcinogens present in tobacco.,drugs .etc

4 mitosis occurs in plants animals

Binary fission occurs in bacteria and other single celled organism.

Both give rise to two daughter cells.

5.sex cells (n) are produced by meiosis from gamete mother cells(2n).

6.in meiosis ploidy of cell become half

Means diploid cell form haploid cells

And 4 haploid daughters cells are formed.

In mitosis, ploidy of cell remain same

Means haploid form haploid and diploid form diploid.

1 cell form 2 daughter cells.

Hope this helps you.. Frnd ❤️

4 0

3 years ago