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MA_775_DIABLO [31]
3 years ago
15

A number cube has sides numbered 1 through 6. The probability of rolling a 2 is 16

Mathematics
2 answers:
anastassius [24]3 years ago
6 0
Well since you have 1/6 chances of getting a 2 you would have 5/6 chances of getting a 2
hope that helps
ser-zykov [4K]3 years ago
3 0
Hello there.

<span>A number cube has sides numbered 1 through 6. The probability of rolling a 2 is 16
what is the probability of not rolling a 2?

Answer: I'm guessing that by 16 you meant 1/6. Therefore you do 6/6 - 1/6 = 5/6,
Therefore the answer is 5/6.

Hope This Helps You!
Good Luck Studying ^-^</span>
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You are designing a rectangular poster to contain 7575 in2 of printing with a 33​-in margin at the top and bottom and a 11​-in m
erma4kov [3.2K]

Answer:

The dimensions of the rectangular poster is 15 in by 5 in.

Step-by-step explanation:

Given that, the area of the rectangular poster is 75 in².

Let the length of the rectangular poster be x and the width of the rectangular poster be y.

The area of the poster = xy in².

\therefore xy=75

\Rightarrow y=\frac{75}{x}....(1)

1 in margin at each sides and 3 in margin at top and bottom.

Then the length of printing space is= (x-2.3) in

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                                                  =(y-2) in

The area of the printing space is A =(x-6)(y-2) in²

∴ A =(x-6)(y-2)

Putting the value of y

\Rightarrow A =(x-6)(\frac{75}{x}-2)

\Rightarrow A = 87-\frac{450}{x}-2x

Differentiating with respect to x

A '= \frac{450}{x^2}-2

Again differentiating with respect to x

A''=-\frac{900}{x^3}

To find the minimum area of printing space, we set A' = 0

\therefore \frac{450}{x^2}-2=0

\Rightarrow 450 =2x^2

\Rightarrow x^2=225

\Rightarrow x=\pm 15

Now putting x=±15 in A''

A''|_{x=15}=-\frac{900}{15^3}

A''|_{x=-15}=-\frac{900}{(-15)^3}=\frac{900}{(15)^3}>0

Since at x=15 , A"<0 Therefore at x=15 , the area will be minimize.

From (1) we get

y=\frac{75}{x}

Putting the value of x

y=\frac{75}{15}

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3 years ago
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Answer:

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Step-by-step explanation:

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