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Studentka2010 [4]
3 years ago
14

3,984,896 rounded to the nearest hundred

Mathematics
1 answer:
ziro4ka [17]3 years ago
4 0

Answer:

3,984,896 rounded to the nearest hundred is 3,984,900

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Which of the following expressions are equivalent to \dfrac{-10}{3}
andreyandreev [35.5K]

Answer:

B

Step-by-step explanation:

I don't know how to explain it, but I hope I got it right and that it helped you.

7 0
1 year ago
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0.27 x 0.03 PLEASE EXPLAIN THE ANSWER! HOW DID YOU GET THE SUM??<br><br><br> I NEED HELP PLEASE!
kow [346]
It would be 0.008 because you line up the decimals and multiply
8 0
3 years ago
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Please hellllllllppppppppppppppppppppppppppp
vitfil [10]

Answer:

21^{10}

Step-by-step explanation:

First, multiply the 3 and the 7 together, and then "multiply" the exponents -8 and 3. (However, when "multiplying exponents, you're really just adding them together: -8 + 5)

(21^{-5})^2

Then, multiply the -5 and -2 together, giving you:

21^{10}

5 0
3 years ago
Trina is purchasing a new bike the store is having 20% off sale and she as 10% coupon of the sale price if the original price of
marusya05 [52]
20% of 89.75 is 17.95
\frac{20}{100}  =  \frac{x}{89.75}  \\ x =  \frac{89.75 \times 20}{100} =  \frac{1795}{100}  = 17.95
so :
89.75 - 19.95 = 71.8
the Trina's coupon will subtract the answer by 10%:

10%of 71.8 is 7.18
\frac{10}{100}  =  \frac{x}{71.8}  \\ x =  \frac{71.8 \times 10}{100}  =  \frac{718}{100}  = 7.18
so the final answer is:
71.8 - 7.18 = 64.62
she has to pay $64.62
hope this helps
8 0
3 years ago
In a randomized controlled trial in Kenya, insecticide treated bednets were tested as a way to reduce malaria. Among 343 infants
Dovator [93]

Answer:

Step-by-step explanation:

Given that in a randomized controlled trial in Kenya, insecticide treated bednets were tested as a way to reduce malaria. Among 343 infants using bednets, 15 developed malaria. Among 294 infants not using bednets, 27 developed malaria.

H0: p1=p2

H1: p1 <p2

(one tailed test)

p1 = 15/343:p2 =27/294:

Difference 4.813 %

95% CI 0.9160% to 9.0217%

Chi-squared 5.947

DF  1

Significance level P = 0.0073

Since p <0.01 we reject null hypothesis.

4 0
3 years ago
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