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RoseWind [281]
3 years ago
8

Which of the following will NOT facilitate the transfer of oxygen to tissues?

Biology
1 answer:
bija089 [108]3 years ago
4 0

Answer:

decreased body temperature

Explanation:

Muscles also need oxygen to function properly. Given that blood flow must be maintained at high levels to supply oxygenation and muscle substrates, mechanisms have been found to facilitate this process. Among the processes that facilitate the transfer of oxygen to tissues, we can mention lowering blood pH, increasing carbon dioxide and increasing exercise.

Lower body temperature, in turn, makes it difficult to transfer oxygen to tissues, causing fatigue, pain and other problems.

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Why would it be beneficial for a plant to have more than one type of plant pigment?
Liula [17]
<span>Because the plant interacts with light to absorb only certain wavelengths, pigments are useful to plants and other autotrophs --organisms which make their own food using photosynthesis. In plants, algae, and cyanobacteria, pigments are the means by which the energy of sunlight is captured for photosynthesis.</span>
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3 years ago
Cellular respiration is the process in which glucose is broken down into carbon dioxide and water, releasing cellular energy in
PIT_PIT [208]

B. Mitochondria

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8 0
3 years ago
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The CRISPR/Cas9 system can cleave genomic DNA at sequences other than the desired target, a phenomenon referred to as off target
Deffense [45]

Answer:

The minimum length of a sgRNA sequence to avoid off target cleavage by the CRISPR/Cas system in the fly fruit genome is 14 bases

Explanation:

We are trying to use the CRISPR/Cas system to cleavage the genome of the fruit fly (which is 1.4x10^8 bp long). Also we desire the cleavage to be unique. That means we need a target sequence long enough to be able to assume it will only appear once in the genome.

First, we should think that in every position, we can find one out of four different nucleotide (A, C, T, G). So, the probability of getting a sequence of a given length "n" will be (1/4)^n (We are assuming that the probability of finding a nucleotide in the position "i", it's independent of the nucleotide we find in any other position "j").

Also, to know how many times a sequence will appear in a genome (the expected value of occurrence), we must multiply the probability of that sequence to randomly occur by the length of the genome. For our specific example, the number of occurence of a sequence of length "n" is:

nºoccurence=[(1/4)^n]*1.4*10^8

But in this case, what we want is the expected number of times the sequence will appear to be 1, and we want to obtain the length of the target sequence (n).

Given the information above, we know that:

[(1/4)^n]*1.4*10^8 =1

[(1/4)^n]=(1/1.4*10^8)=1.4*10^-8

Then, if we want to calculate n, we can use logarithms and its properties to get:

log[(1/4)^n]=log[1.4*10^-8]

n*log[(1/4)]=log[1.4*10^-8]

n=log[1.4*10^-8]/log[(1/4)] => n=13.29 approximately.

As the sequence needs to have a natural number of elements, <u>we can conclude that using a target sequence of a minimum of 14 bases with the CRISPR/Cas system in the fly fruit genome should be enough to avoid off target cleavage.</u>

3 0
3 years ago
Between which two letters does mitosis occur
sdas [7]
One of them i think is biolorgy with 5th and 6th
6 0
3 years ago
I have to divide 6 by 77777
Semmy [17]

Answer:

6 divide by 77777=0.00007714362

hope it helps

8 0
3 years ago
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