Potassium, 4 shells, 1 valence electron
<h3><u>Answer;</u></h3>
Active transport uses energy and passive transport does not
<h3><u>Explanation</u>;</h3>
- <u>Passive transport occurs when materials move across cell membranes without using cell energy (ATP). </u> Examples of passive transport include; diffusion, facilitated diffusion, and osmosis. It moves small molecules like water, oxygen, carbon dioxide and glucose.
- <em><u>Active transport on the other hand involves the movement of materials across the cell membrane that requires the use of cell energy (ATP)</u></em>.
- In other words the difference between active transport and passive transport is that passive Transport moves ions from high concentration to low, using no metabolic energy while active Transport moves ions from low concentration to high, using metabolic energy in the form of ATP.
It would probably be .D. Plankton populations decreasing.
Answer:option C= mRNA
Explanation:
MACROMOLECULES are large molecules, such as protein, commonly created by the polymerization of smaller sub-units called monomers.
The NUCLEAR PORE is a protein-lined channel in the nuclear envelope. The NUCLEAR PORE regulates the transportation of molecules between the nucleus and the cytoplasm. In eukaryotic cells, the nucleus is separated from the cytoplasm and surrounded by a nuclear envelope.
mRNA is synthesized by DNA during a process known as the TRANSCRIPTION. After the synthesis, the new molecule moves from the nucleus to the cytoplasm. It passes through the nuclear membrane through a NUCLEAR PORE. Then, it will later join with a ribosome, which is just coming together from its two sub-units, one large and one small.
Answer : The dissociation constant of the PFK‑inhibitor complex is, 5 µM
Explanation :
The expression for reversible competitive inhibition when apparent Km affected by addition of the inhibitor is:
![K_m_a=K_m[1+\frac{I}{K_i}]](https://tex.z-dn.net/?f=K_m_a%3DK_m%5B1%2B%5Cfrac%7BI%7D%7BK_i%7D%5D)
where,
= apparent value = 52 µM
= Michaelis–Menten constant = 40 µM
I = inhibitor concentration = 1.5 µM
= dissociation constant of the PFK‑inhibitor complex
Now put all the given values in the above formula, we get:
![52\mu M=40\mu M[1+\frac{1.5\mu M}{K_i}]](https://tex.z-dn.net/?f=52%5Cmu%20M%3D40%5Cmu%20M%5B1%2B%5Cfrac%7B1.5%5Cmu%20M%7D%7BK_i%7D%5D)
Therefore, the dissociation constant of the PFK‑inhibitor complex is, 5 µM
