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damaskus [11]
3 years ago
11

Your locomotive is 16 inches long. It is an exact model of the locomotive that is 40 feet long. A window on the locomotive this

how many times wider than a window on the model?
Mathematics
2 answers:
elena55 [62]3 years ago
8 0

Answer:

A window on the locomotive is 30 times wider than a window on the model

Step-by-step explanation:

we know that

If two figures are similar, then the scale factor is equal to divide the length of its corresponding sides

In this problem

the scale factor is

\frac{16}{40}\ \frac{in}{ft}

Remember that

1\ ft=12\ in

so

\frac{16}{40}\ \frac{in}{ft}=\frac{16}{40*12}=\frac{16}{480}\ \frac{in}{in}

Simplify

\frac{1}{30}\ \frac{in}{in}=\frac{1}{30}

That means----> 1 unit in the model represent 30 units on the locomotive

therefore

A window on the locomotive is 30 times wider than a window on the model

olga_2 [115]3 years ago
4 0

Answer:

30 times wider

Step-by-step explanation:

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A study conducted by the Center for Population Economics at the University of Chicago studied the birth weights of 623 babies bo
Margaret [11]

Answer:

The estimation for the number of newborns who weighed between 1724 grams and 5172 grams is 595.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 3448, \sigma = 862

Proportion of newborns who weighed between 1724 grams and 5172 grams.

This is the pvalue of Z when X = 5172 subtracted by the pvalue of Z when X = 1724. So

X = 5172

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{5172 - 3448}{862}

Z = 2

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X = 1724

Z = \frac{X - \mu}{s}

Z = \frac{1724 - 3448}{862}

Z = -2

Z = -2 has a pvalue of 0.0228

0.9772 - 0.0228 = 0.9544

Estimate the number of newborns who weighed between 1724 grams and 5172 grams.

0.9544 out of 623 babies. SO

0.9544*623 = 595

The estimation for the number of newborns who weighed between 1724 grams and 5172 grams is 595.

5 0
3 years ago
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brilliants [131]

Answer:

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