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drek231 [11]
3 years ago
13

A person purchased a leather jacket that was marked down by 40%. if the sale price of the jacket was $101.79, what was its origi

nal price?
Mathematics
1 answer:
Rama09 [41]3 years ago
5 0
The original price was $142.50. What I did was that I added 40% with $101.79 which was the sales price. With the 40% the person saved $40.71.

Hope this helps : )*****
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Answer:

a

  P(X = 0) =  0.6065

b

P(x <  25 ) =   1.18 *10^{-33}

c

 P(x \le 5 ) =  0.9994    

Step-by-step explanation:

From the question we are told that

  The rate  is \lambda =  \frac{1}{2}\   hr^{-1}    =  0.5 / hr

  Generally  Poisson distribution formula is mathematically represented as

       P(X = x) =  \frac{(\lambda t) ^x e^{-\lambda t }}{x!}

Generally the probability that no error occurred during a day is mathematically represented as  

Here  t =  1  hour according to question a

So

   P(X = x) =  \frac{\lambda^x e^{-\lambda}}{x!}

Hence

   [tex]P(X = 0) =  \frac{\frac{1}{2} ^0 e^{-\frac{1}{2}}}{0!}

=>  P(X = 0) =  0.6065

Generally the probability that  a critical error occurs since the start of a day is mathematically represented as

Here  t =  1  hour according to question a

So

   P(X = x) =  \frac{\lambda^x e^{-\lambda}}{x!}

Hence

      P(x \ge 25 ) =  1 - P(x <  25 )

Here

     P(x <  25 ) = \sum_{x=0}^{24} \frac{e^{-\lambda} * \lambda^{x}}{x!}

=>   P(x <  25 ) =  \frac{e^{-0.5} *0.5^{0}}{0!} + \cdots + \frac{e^{-0.5} *0.5^{24}}{24!}

P(x <  25 ) =  0.6065 + \cdots + \frac{e^{-0.5} *0.5^{24}}{6.204484 * 10^{23}}

P(x <  25 ) =  0.6065 + \cdots + 6.0*10^{-32}

P(x <  25 ) =   1.18 *10^{-33}

Considering question c

Here  t =  2  

Gnerally given that the  system just started up and an error occurred  the probability the next reset will occur within 2 hours

P(x \le 5 ) =  \sum_{n=0}^{5}  \frac{(\lambda t) ^x e^{-\lambda t }}{x!}

=> P(x \le 5 ) =   \frac{(0.5 *  2) ^ 0 e^{- 0.5  * 2 }}{0!} + \cdots  +   \frac{(0.5 *  2) ^ 5  e^{- 0.5  * 2 }}{5!}

=> P(x \le 5 ) =   \frac{1* 2.7183 }{1 } + \cdots  +   \frac{1  *2.7183 }{120}

=>  P(x \le 5 ) =   2.7183 + \cdots  +   0.0226525

 P(x \le 5 ) =  0.9994    

8 0
3 years ago
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