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Elena-2011 [213]
3 years ago
14

Which size random sample is likely to provide the most trustworthy results?

Mathematics
2 answers:
irina1246 [14]3 years ago
8 0
A is your best answer. The more you have the better
podryga [215]3 years ago
5 0
50.
A bigger sample usually gives more trustworthy results.
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How do you solve 135x42? (step by step please)
mojhsa [17]

Answer:

5,670

Step-by-step explanation:

how do you solve 135x42? (step by step please)

Answer :

= 135 x 42

= 5,670

3 0
3 years ago
Solve the inequality.
svetlana [45]

Answer:

Step-by-step explanation:

n ≥ -2 + 9

n ≥ 7

3 0
3 years ago
Read 2 more answers
The wheels on Darlene's car have on 11-inch radius. If the wheels are rotating at a rate of 378 rpm, find the linear speed in mi
elena-s [515]

Answer:

The linear speed in which Darlene is traveling is 24.74 miles per hour.

Step-by-step explanation:

The wheel experiments rolling, which is a combination of translation and rotation. The point where linear speed happens is located at geometrical center of the wheel and instantaneous center of rotation is located at the point of contact between wheel and ground. The linear speed (v), measured in inches per second, is defined by following expression:

v = R\cdot \omega (1)

Where:

R - Radius of the wheel, measured in inches.

\omega - Angular speed, measured in radians per second.

If we know that R = 11\,in and \omega \approx 39.584\,\frac{rad}{s}, then the linear speed, measured in miles per hour, in which Darlene is traveling is:

v = 11\,in\times \frac{1\,mi}{63360\,in} \times 39.584\,\frac{rad}{s}\times \frac{3600\,s}{h}

v \approx 24.74\,\frac{mi}{h}

The linear speed in which Darlene is traveling is 24.74 miles per hour.

8 0
3 years ago
Isabelle rides her bike to school. The graph shows her speed at different times during her ride.
kipiarov [429]

Answer:

0 to 2 minutes - Accelerating

3 to 4 minutes - Constant

6 to 8 minutes - Decelerating

9 to 11 minutes Accelerating

hope i have helped u

Step-by-step explanation:

3 0
2 years ago
In a tutoring session, 2/3 of an hour was spent reviewing math problems. Adelina attended 3/4 of the tutoring session. How much
fgiga [73]

Answer:

Time spend by Adelina at the tutoring session is 30 minutes.

Step-by-step explanation:

Given : In a tutoring session, \frac{2}{3} of an hour was spent reviewing math problems and Adelina attended \frac{3}{4} of the tutoring session.

We have to find the time Adelina spend at the tutoring session.

We know, 1 hour = 60 minutes.

Total time taken in tutoring session = \frac{2}{3}\times 60=40 minutes.

also, Adelina attended \frac{3}{4} of the tutoring session that is \frac{3}{4} of 40 minutes.

that is \frac{3}{4}\times 40=30minutes.

Thus, time spend by Adelina at the tutoring session is 30 minutes.


 

4 0
3 years ago
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