Answer:
250 miles
Step-by-step explanation:
The given distance between the house and the beach is 125 miles.
Let 
miles be the distance between the house and the lunch stop.
So, at the time of the lunch stop, he already traveled miles, the remaining distance is the distance between the lunch stop and the beach.
Let 
miles be the remaining distance, so
Give that the ratio of the distance he has traveled, , to the distance he still has to travel, , is 
,i.e
Hence, the distance traveled by Herman when he stops for lunch is 250 miles.
Answer:
(x - 5)(x + 3)
Step-by-step explanation:
to solve x² - 2x = 15, we need to get all the terms on one side so we can solve the quadratic equation using factoring. to do this, we subtract 15 from both sides
x² - 2x = 15
- 15 -15
x² - 2x - 15 = 0
now we can factor. we need 2 numbers that when multiplied together give us -15, and when those 2 numbers are added together we get -2
because we have a -15, we can assume that one number must be negative and the other positive, as a negative times a postive is a negative.
we can use 3 and -5 as factors and test it out. we put x in front because we have an x²
(x - 5)(x + 3) < we can FOIL to check to see if this is correct. its not mandatory to check but when you arent sure of the answer you can FOIL it out
FOIL stands for: First, Outside, Inside, and Last terms
F: (x - 5)(x + 3) = x²
O: (x - 5)(x + 3) = -3x
I: (x - 5)(x + 3) = 5x
L: (x - 5)(x + 3) = -15
x² + 3x - 5x - 15 < subtract 3x from 5x
x² - 2x - 15
this checks out, so our answer is (x - 5)(x + 3)
Answer
Option C : 2214(5)
Solution
The given number is 465 in base 8. To convert this number to base 5,we need to convert this number to base 10, then only we can compute the number in base 5
Step1 : Convert 465 to the base 8 to base 10
4 x 82=256
6 x 81=48
5 x 80=5
Adding 256 + 48+ 5 = 309(10)
Step2 : Convert 309(10) to base 5
5 | 309
5 | 61 |4
5 | 12 | 1
5 | 2 | 2
5 | 0 | 2
Therefore Answer = 2214(5 )
I believe the answer is letter D
Answer: 3∛2
<u>Step-by-step explanation:</u>
First, factor 128 .... you need three common factors to bring one on the outside of the radical.
![\dfrac{3}{4}\sqrt[3]{128} \\\\\\=\dfrac{3}{4}\sqrt[3]{4\cdot 4\cdot 4\cdot 2} \\\\\\=\dfrac{3}{4}\cdot 4\sqrt[3]{2} \\\\\\=\large\boxed{3\sqrt[3]{2} }](https://tex.z-dn.net/?f=%5Cdfrac%7B3%7D%7B4%7D%5Csqrt%5B3%5D%7B128%7D%20%5C%5C%5C%5C%5C%5C%3D%5Cdfrac%7B3%7D%7B4%7D%5Csqrt%5B3%5D%7B4%5Ccdot%204%5Ccdot%204%5Ccdot%202%7D%20%5C%5C%5C%5C%5C%5C%3D%5Cdfrac%7B3%7D%7B4%7D%5Ccdot%204%5Csqrt%5B3%5D%7B2%7D%20%5C%5C%5C%5C%5C%5C%3D%5Clarge%5Cboxed%7B3%5Csqrt%5B3%5D%7B2%7D%20%7D)
