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qwelly [4]
2 years ago
14

PLs help me 30 points in total

Mathematics
1 answer:
Rzqust [24]2 years ago
3 0

Answer:

5. 11 1/12 or 133/12

6. 8/15

Step-by-step explanation:

5. make them have a common denominator and then add

6. multiply 2/3 * 4/5

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11t - 6t = 45 solve the equation and enter the value of t below ​
Arada [10]

Answer:

t = 9

Step-by-step explanation:

11t - 6t = 45

5t = 45

<h3>t =  \frac{45}{5}</h3>

t = 9

<h3>Hope it is helpful....</h3>
8 0
3 years ago
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How do you solve #3? The one that is incorrect.
Sunny_sXe [5.5K]
Infinite they’re all multiples, so they are the same line
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Simplify the expression 5+4+2(-3)+7+(-5)
liberstina [14]
Just use pemdas
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3 years ago
The side of one square is equal to 3m and its diagonal is equal to the side of a second square. Find the diagonal of the second
navik [9.2K]

Answer:

6m

Step-by-step explanation:

the side of first square = 3 m

area of first square = 3^2= 9 m^2

let the side of second square = x m

since diagonal of first square = x m as per the question

in a square each angle is 90 degree

therefore by applying pythagorus theorem ,

diagonal ^2 = side^2 + side ^2

diagonal^2 = 3^2+3^2=9+9

DIAGONAL= square root of 18

diagonal= 3\sqrt{2} m = side of second square

therefore in second square ,

one angle is 90  degree , therefore by applying pythagorue theorem

diaqonal^2 = side ^2 + side ^2 = (3\sqrt{2})^2 + ( 3\sqrt{2})^2

diagonal ^2 = 18 + 18

diagonal = square root of 36

therefore diagonal of second square is 6m

hope it helps you... please mark me as the brainliest..

8 0
3 years ago
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Solve for x.<br> -6x = -18
marta [7]

Answer:

3

Step-by-step explanation:

The goal is to get the x to be on one side of the equation on its own.

-6x = -18

To get rid of the -6, we would have to do the opposite of what it's doing in the equation - in this case, we would divide, as it's the opposite of multiplying.

What we do to one side of the equation, we have to do to the other.

-6x/-6 = x

-18/-6 = 3

x = 3

Hope that makes sense!

3 0
3 years ago
Read 2 more answers
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