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Dmitry_Shevchenko [17]
3 years ago
8

Distance between (5,0) and (2,-2)

Mathematics
1 answer:
GuDViN [60]3 years ago
4 0

Answer: d(distance) = \sqrt13\\

Hope this help!

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The problem below has been solved incorrectly. Identify and explain the error.
mylen [45]

Answer:

If you look over the steps you can see that until 4x + x + 3 = 18, evertything is dandy. But the step after that 4x + x =21 seems a bit fishy.

Think about it they subtract 3 from both sides so the first side is correct

4x + x, but they added 3 to the other side:

(4x+x+3) - 3 = 18 - 3\\4x+x = 15

not

4x+x = 21

Then we solve for 4x + x = 15

5x = 15\\x = \frac{15}{5} \\x = 3

To solve for y we use :

y = x+3

y = 3+3 = 6

so (3,6) is the right answer

7 0
2 years ago
Jenny earned a 77 on her most recent test. Jenny’s score is no less than 5 points greater than Four-fifths of Terrance’s score.
lina2011 [118]

77 5 + 4/5t

Is the answer!

4 0
3 years ago
Read 2 more answers
How can you 24 with the numbers 6,6,2,1
Andreas93 [3]

Add 6 + 6 = 12

Multiple 12 * 2 = 24

Multiple 24 * 1 = 24

5 0
3 years ago
Rice is being poured into a cylindrical container with radius 4.5 inches so
12345 [234]

asked:the istant of height is the same as the radius

given facts:cylindrical container with radius 3.5 inches height of rice increasing 0.5 inches per second

solve hidden given:(4.5+o.5+2)

what operation to be used: addition and subtraction

solve+4.5+05+2=6.0

chec: 6.0-4.5=1.5

8 0
2 years ago
If IM is reflected across the x-axis and then translated along the vector <4, 1>, in
taurus [48]

Answer:

Final image L"M" will lie in the fourth quadrant.

Step-by-step explanation:

Coordinates of the ends of segment LM,

L  → (-3, 4)

M → (-3, 2)

Rule to reflect a point across x-axis is,

(x, y) → (x, -y)

By this rule, coordinates of the image point of L and M will be,

L(-3, 4) → L'(-3, -4)

M(-3, 2) → M'(-3, -2)

Further these image points are translated along the vector <4, 1>

Rule for this translation will be,

(x, y) → (x + 4, y + 1)

Now the image points of the points L' and M' will be,

L'(-3, -4) → L"(-3 + 4, -4 + 1)

             → L"(1, -3)

M'(-3, -2) → M"(-3 + 4, -2 + 1)

              → M"(1, -1)

Therefore, final image L"M" will lie in the fourth quadrant.

7 0
2 years ago
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