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Step2247 [10]
3 years ago
6

Find the value of x that would make line p parallel to line r

Mathematics
1 answer:
Snowcat [4.5K]3 years ago
4 0
There is a theorem that says if parallel lines are cut by a transversal, then same-side interior angles are supplementary (add up to 180 degrees).

If lines p and r were parallel, then angles 28 and (3x + 2) would add up to 180 degrees.

(28) + (3x + 2) = 180
3x + 30 = 180
3x = 150
x = 50
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Which expression is equivalent to sqrt8x^7y^8? assume x>0
Ilia_Sergeevich [38]

Answer:

\sqrt{8x^7y^8= 2x^3y^4 * \sqrt{2x}

Step-by-step explanation:

Given

\sqrt{8x^7y^8

Required

Evaluate

\sqrt{8x^7y^8

Separate each factor with multiplication sign

\sqrt{8*x^7*y^8

Express 8 as 4 * 2 and x^7 as x^6 * x

\sqrt{4 * 2 *x^6 * x*y^8

Split each factor

\sqrt{4} * \sqrt{2} *\sqrt{x^6} * \sqrt{x}*\sqrt{y^8}

Evaluate \sqrt4

2 * \sqrt{2} *\sqrt{x^6} * \sqrt{x}*\sqrt{y^8}

Apply law of indices:

2 * \sqrt{2} * x^{6*\frac{1}{2}} * \sqrt{x} * y^{8*\frac{1}{2}}

2 * \sqrt{2} * x^3 * \sqrt{x} * y^4

Reorder

2* x^3 * y^4 * \sqrt{2}  * \sqrt{x}

2x^3y^4 * \sqrt{2}  * \sqrt{x}

2x^3y^4 * \sqrt{2*x}

2x^3y^4 * \sqrt{2x}

2x^3y^4 \sqrt {2x

Hence:

\sqrt{8x^7y^8= 2x^3y^4 * \sqrt{2x}

8 0
3 years ago
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What value of t is the solution of the above equation?
mel-nik [20]

Answer:

15/4, or 3 3/4 is your answer.

Step-by-step explanation:

Isolate the variable, t. Note the equal sign, what you do to one side, you do to the other. Multiply 3/2 to both sides.

(3/2)(2/3)t = (5/2)(3/2)

t = (5/2)(3/2)

t = 15/4

15/4, or 3 3/4 is your answer.

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7 0
4 years ago
If y=-18 when x=6 find x when y=6
torisob [31]

Answer:

X=-2

Step-by-step explanation:  x is negative 1/3 of y. We can tell because of this example so when you divide y=6 by negative 1/3 it makes -2!

5 0
4 years ago
Find the value of x, y, and z if<br> 5<br> X=<br> y =<br> Z=
BlackZzzverrR [31]

Answer:

x = 12

y = 9

z = 11

Step-by-step explanation:

so, let's just do all the calculations in there :

(3×5)⁴ = 3⁴×5⁴

(2×3)⁵ = 2⁵×3⁵

(2×5)⁷ = 2⁷×5⁷

multiplying all 3 terms is then

3⁴×5⁴×2⁵×3⁵×2⁷×5⁷

more let's "group" and combine these terms based on the bases of the power operations, as we need to get an expression showing 2, 3 and 5 with their powers.

so, for the base of 2 we have

2⁵×2⁷ = 2¹²

for the base of 3 we have

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fire the base of 5 we have

5⁴×5⁷ = 5¹¹

so we get

2¹² × 3⁹ × 5¹¹

=>

x=12

y=9

z=11

6 0
3 years ago
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