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2 years ago

Given the data below which set of numbers contains the lower quartile median and upper quartile help fast please !!

Mathematics

2 answers:

natta225 [31]2 years ago

6 0

Answer:

{27.5, 29, 34}

Step-by-step explanation:

Arrange in increasing order :

24, 27, 28, 28, 29, 31, 32, 36, 38

Lower Quartile :

24 + 27 + 28 + 28 / 4
107/4
26.75 ≈ 27.5 (closest based on options)

Median :

5th term
29

Upper Quartile :

31 + 32 + 36 + 38 / 4
137/4
34.25 ≈ 34

bezimeni [28]2 years ago

5 0

Answer:

{27.5, 29, 34}.

Step-by-step explanation:

In order they are

24 27 28 28 29 31 32 36 38

The Median = middle value = 29.

Lower quartile = mean of 27 and 28 = 27.5.

Upper quartile = mean of 32 and 36 = 34.

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the scale on a map se oanchows 5 centimeters equals 2 kilometers what nuumber of centimeters on the map represents an actual dis

Igoryamba

12.5 cm equals 5 km.

8 0

3 years ago

A line with a slope of 1/8 passes through the points (u, -9) and (6, -8). what is the value of u?

Pie

Answer:
u = -2

Explanation:
Slope of the line can be calculated using the following rule:
slope = (y2-y1) / (x2-x1)

We are given :
slope = 1/8
point (u,-9) represent (x1,y1)
point (6,-8) represent (x2,y2)

Substitute with the givens in the above equation and solve for u as follows:
slope = (y2-y1) / (x2-x1)
1/8 = (-8--9) / (6-u)
1/8 = (1) / (6-u)
1* (6-u) = 1*8
6-u = 8
u = 6-8
u = -2

Hope this helps :)

6 0

3 years ago

At the bike shop x, it cost $2.75 per hour plus a $3.00 deposit to rent a bike.AT Bike shop z cost $1.75 per hour plus a $7.00 d

Alex_Xolod [135]

Multiply the rate per hour by the number of hours (n) and add the deposit.

Bike shop x: c = 2.75n + 3.00

Bike shop z: c = 1.75n + 7.00

B) to find when they will cost the same set the equations equal to each other and solve for n:

2.75n + 3.00 = 1.75n + 7.00

Subtract 3 from each side:

2.75n = 1.75n + 4.00

Subtract 1.75n from both sides:

1.00n = 4.00

Divide both sides by 1:

n = 4 hours

6 0

3 years ago

The average transaction at an automatic teller can be completed in six minutes and customers arrive at the average rate of one e

lorasvet [3.4K]

Answer:

Zero, based on the information provided.

Step-by-step explanation:

The output rate of the teller machine is (1 transaction/6 minutes). The input rate is (1 customer/10 minutes). This means that the machine completes a cycle faster than the customers arrive, on the average. I don't know how an average can be calculated without more information. If we assume customers arrive every 10 minutes, and no one screws up the machine, that there should be no waiting line. Is there more information about when the customers arrive? E.g., 50 arrive in the first hour the machine is open.

8 0

2 years ago

A. Do some research and find a city that has experienced population growth.

horrorfan [7]

A. The city we will use is Orlando, Florida, and we are going to examine its population growth from 2000 to 2010. According to the census the population of Orlando was 192,157 in 2000 and 238,300 in 2010. To examine this population growth period, we will use the standard population growth equation $N_{t} =N _{0}e^{rt}$
where:
$N(t)$ is the population after $t$ years
$N_{0}$ is the initial population
$t$ is the time in years
$r$ is the growth rate in decimal form
$e$ is the Euler's constant
We now for our investigation that $N(t)=238300$ , $N_{0} =192157$ , and $t=10$ ; lets replace those values in our equation to find $r$ :
$238300=192157e^{10r}$
$e^{10r} = \frac{238300}{192157}$
$ln(e^{10r} )=ln( \frac{238300}{192157} )$
$r= \frac{ln( \frac{238300}{192157}) }{10}$
$r=0.022$
Now lets multiply $r$ by 100% to obtain our growth rate as a percentage:
$(0.022)(100)$ =2.2%
We just show that Orlando's population has been growing at a rate of 2.2% from 2000 to 2010. Its population increased from 192,157 to 238,300 in ten years.

B. Here we will examine the population decline of Detroit, Michigan over a period of ten years: 2000 to 2010.
Population in 2000: 951,307
Population in 2010: 713,777
We know from our investigation that $N(t)=713777$ , $N_{0} =951307$ , and $t=10$ . Just like before, lets replace those values into our equation to find $r$ :
$713777=951307e^{10r}$
$e^{10r} = \frac{713777}{951307}$
$ln(e^{10r} )=ln( \frac{713777}{951307} )$
$r= \frac{ln( \frac{713777}{951307}) }{10}$
$r=-0.029$
$(-0.029)(100)$ = -2.9%.
We just show that Detroit's population has been declining at a rate of 2.2% from 2000 to 2010. Its population increased from 192,157 to 238,300 in ten years.

C. Final equation from point A: $N(t)=192157e^{0.022t}$ .
Final equation from point B: $N(t)=951307e^{-0.029t}$
Similarities: Both have an initial population and use the same Euler's constant.
Differences: In the equation from point A the exponent is positive, which means that the function is growing; whereas, in equation from point B the exponent is negative, which means that the functions is decaying.

D. To find the year in which the population of Orlando will exceed the population of Detroit, we are going equate both equations $N(t)=192157e^{0.022t}$ and $N(t)=951307e^{-0.029t}$ and solve for t:
$192157e^{0.022t} =951307e^{-0.029t}$
$\frac{192157e^{0.022t} }{951307e^{-0.029t} } =1$
$e^{0.051t} = \frac{951307}{192157}$
$ln(e^{0.051t})=ln( \frac{951307}{192157})$
$t= \frac{ln( \frac{951307}{192157}) }{0.051}$
$t=31.36$
We can conclude that if Orlando's population keeps growing at the same rate and Detroit's keeps declining at the same rate, after 31.36 years in May of 2031 Orlando's population will surpass Detroit's population.

E. Since we know that the population of Detroit as 2000 is 951307, twice that population will be $2(951307)=1902614$ . Now we can rewrite our equation as: $N(t)=1902614e^{-0.029t}$ . The last thing we need to do is equate our Orlando's population growth equation with this new one and solve for t:
$192157e^{0.022t} =1902614e^{-0.029t}$
$\frac{192157e^{0.022t} }{1902614e^{-0.029t} } =1$
$e^{0.051t} = \frac{1902614}{192157}$
$ln(e^{0.051t} )=ln( \frac{1902614}{192157} )$
$t= \frac{ln( \frac{1902614}{192157}) }{0.051}$
$t=44.95$
We can conclude that after 45 years in 2045 the population of Orlando will exceed twice the population of Detroit.

8 0

3 years ago