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Lubov Fominskaja [6]
3 years ago
7

Arial says that, for any pair of linear relations, if the coefficients of the y-terms are equal and the coefficients of the x-te

rms are equal, the graphs of the two lines will be parallel.
a. Give an example for which Arial's claim is true.

b. Give an example for which Arial's claim is false.

c. Suggest an improvement to Arial's claim.
Mathematics
1 answer:
wel3 years ago
4 0

Answer:

<h3>a. Give an example for which Arial's claim is true.</h3>

If linear relations have equal coefficient about the independent variable, then those linear relations are parallel. For example, y=3x+4 and y=3x-5.

Notice that the coefficient of the dependent variable must be also equal, otherwise it would change the slope of the expression and they wouldn't be parallel.

<h3>b. Give an example for which Arial's claim is false. </h3>

The statement is not false.

<h3>c. Suggest an improvement to Arial's claim.</h3>

An improvemente would be that the constant term no need to be equal too, between linear relations, because they can be at "differecent heights", sort of speak.

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The element that has exactly 5 protons in its nucleus would be:

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Are the given values in the table enough information to show an exponential function instead of a linear function? If not, expla
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Step-by-step explanation:

Are the given values in the table enough information to show an exponential function instead of a linear function? If not, explain why not then write the equations for both an exponential and linear function represented by the table.

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3 years ago
The function F is defined by F(x)=x^2+3X-10
vesna_86 [32]

Answer:

k = 13

smallest zero = -6

Step-by-step explanation:

f(x) is basically the function of x.

x could be any integer. f(x) is the solution of the function of x.

f(x) is defined as x² + 3x - 10

f(x) = x² + 3x - 10

Now, f(x+5) = x² + kx + 30

This statement here says that if the value of x is x+5, then the answer would be x² + kx + 30.

f(x) = x² + 3x - 10

f(x+5) = (x+5)² + 3(x+5) - 10

f(x+5) = x² + 10x + 25 + 3x + 15 - 10

f(x+5) = x² + 13x + 40 - 10

f(x+5) = x² + 13x + 30

x² + 13x + 30 = x² + kx + 30

hence, k = 13

Smallest zero = The smallest x value.

f(x+5) = x² + 13x + 30

Let's take f(x+5) = 0

x² + 13x + 30 = 0

which two numbers products give us 30 and add up to 13?

== 6 and 5

(x+6)(x+5) = 0

x+6 = 0

x = -6

x+5 = 0

x = -5

The two solutions are -6 and -5

The smallest out of these two is -6.  

7 0
4 years ago
Which inequality is true?
Whitepunk [10]
A. 100 < 50 False
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8 0
3 years ago
Given that the sec A = 13/5 and A is in QIV, determine exact value for the sin A.
AysviL [449]

Answer:

The exact value of sin A is opp/hyp = -12/13

Step-by-step explanation:

If A is in Quadrant IV then the "opposite side" is negative and the "adjacent side" is positive.  Since sec A = hyp / adj = 13 / 5 and since opp^2 + adj^2 must add up to hyp^2,   Therefore y = √(hyp^2 - adj^2), or

y = -√(13^2 - 25) = -√144 = 12.

The exact value of sin A is opp/hyp = -12/13

6 0
3 years ago
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