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Lubov Fominskaja [6]
4 years ago
7

Arial says that, for any pair of linear relations, if the coefficients of the y-terms are equal and the coefficients of the x-te

rms are equal, the graphs of the two lines will be parallel.
a. Give an example for which Arial's claim is true.

b. Give an example for which Arial's claim is false.

c. Suggest an improvement to Arial's claim.
Mathematics
1 answer:
wel4 years ago
4 0

Answer:

<h3>a. Give an example for which Arial's claim is true.</h3>

If linear relations have equal coefficient about the independent variable, then those linear relations are parallel. For example, y=3x+4 and y=3x-5.

Notice that the coefficient of the dependent variable must be also equal, otherwise it would change the slope of the expression and they wouldn't be parallel.

<h3>b. Give an example for which Arial's claim is false. </h3>

The statement is not false.

<h3>c. Suggest an improvement to Arial's claim.</h3>

An improvemente would be that the constant term no need to be equal too, between linear relations, because they can be at "differecent heights", sort of speak.

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A new sample of 225 employed adults is chosen. Find the probability that less than 7.1% of the individuals in this sample hold m
arsen [322]

Answer:

The probability that less than 7.1% of the individuals in this sample hold multiple jobs is 0.0043.

Step-by-step explanation:

Let <em>X</em> = number of individuals in the United States who held multiple jobs.

The probability that an individual holds multiple jobs is, <em>p</em> = 0.13.

The sample of employed individuals selected is of size, <em>n</em> = 225.

An individual holding multiple jobs is independent of the others.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 225 and <em>p</em> = 0.13.

But since the sample size is too large Normal approximation to Binomial can be used to define the distribution of proportion <em>p</em>.

Conditions of Normal approximation to Binomial are:

  • np ≥ 10
  • n (1 - p) ≥ 10

Check the conditions as follows:

np=225\times 0.13=29.25>10\\n(1-p)=225\times (1-0.13)=195.75>10

The distribution of the proportion of individuals who hold multiple jobs is,

p\sim N(p, \frac{p(1-p)}{n})

Compute the probability that less than 7.1% of the individuals in this sample hold multiple jobs as follows:

P(p

*Use a <em>z</em>-table.

Thus, the probability that less than 7.1% of the individuals in this sample hold multiple jobs is 0.0043.

7 0
3 years ago
Answer quickly!!!!!!!!
Black_prince [1.1K]

Answer:

c: 8   i'm sure

Step-by-step explanation:

Because we count where the line stops is 8 squares which means it's 8

8 0
3 years ago
Read 2 more answers
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