I need help please help
1 answer:
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Answer:
(a) P (none) = 0.005873
(b) P ( at least one household ) = 0.9941
(c) P ( at most one household ) = 0.9960
(d) not wrong
Step-by-step explanation:
Given data
probability P = 29% = 0.29
no of sample n = 15
tv show X = 50
to find out
the probability that none of the households
the probability that at least one household
the probability that at most one household
If at most one household is tuned to 50 Minutes, does it appear that the 19% share value is wrong
solution
the probability that none of the households is tuned to 50 Minutes is
P (none) = 10C0 × ×
P (none) =
P (none) = 0.005873
and the probability that at least one household is tuned to 50 Minutes is
P ( at least one household ) = 1 - P(none)
P ( at least one household ) = 1 - 0.005873
P ( at least one household ) = 1 - 0.005873
P ( at least one household ) = 0.9941
the probability that at most one household is tuned to 50 Minutes is
P ( at most one household ) = P (none) + P (x=1)
P ( at most one household ) =0.9941 + 10C1 × ×
P ( at most one household ) = 0.9960
and in last part If at most one household is tuned to 50 Minutes it appear that the 19% share value is not wrong
because P( at most one household ) is not zero