Answer:
![B=2\times 3^n](https://tex.z-dn.net/?f=B%3D2%5Ctimes%203%5En)
Step-by-step explanation:
<u>Exponential Growing
</u>
Steven currently reads 2 books a year. He wants to triple the number of books read per year. The first year he should read
![2*3 = 6\ books](https://tex.z-dn.net/?f=2%2A3%20%3D%206%5C%20books)
By the second year, he should read
![2*3^2 = 18\ books](https://tex.z-dn.net/?f=2%2A3%5E2%20%3D%2018%5C%20books)
By the third year, he should read
![2*3^3 = 54\ books](https://tex.z-dn.net/?f=2%2A3%5E3%20%3D%2054%5C%20books)
We can clearly see there is a geometric progression of the number of books he should read for the year n. The general formula is, being B the number of books read at the year n
![\boxed{B=2\times 3^n}](https://tex.z-dn.net/?f=%5Cboxed%7BB%3D2%5Ctimes%203%5En%7D)
Answer:
E
Explanation:
well, process of elimination
Exponential growth is
F=P(1+r)^t
F=future amount
P=present amount
r=rate
t=time in years
rate=2%=0.02
therefor the equation is
f(x)=23,000(1+0.02)^x
f(x)=23,000(1.02)^x
where x=time in years from 2012