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Alex Ar [27]
2 years ago
9

Steven wants to increase the number of books he reads per year. He currently reads 2 books a year. He wants to triple the number

of books he reads each year compared to the previous year. Which equation best represents the number of books Steven will read after the nth year?
Mathematics
1 answer:
Sladkaya [172]2 years ago
8 0

Answer:

B=2\times 3^n

Step-by-step explanation:

<u>Exponential Growing </u>

Steven currently reads 2 books a year. He wants to triple the number of books read per year. The first year he should read

2*3 = 6\ books

By the second year, he should read

2*3^2 = 18\ books

By the third year, he should read

2*3^3 = 54\ books

We can clearly see there is a geometric progression of the number of books he should read for the year n. The general formula is, being B the number of books read at the year n

\boxed{B=2\times 3^n}

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A parallelogram has an area of 100 square units its perimeter is between 40 and 60 units list to possible that dimensions for th
Papessa [141]
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7 0
3 years ago
16 is the geometric mean of 8 and what other number?
zepelin [54]
It is also the geometric mean of 4
8 0
3 years ago
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dybincka [34]

Answer:

H. 39.6

Step-by-step explanation:

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4 0
2 years ago
Chapman’s brickyard sells bricks and blocks. A brick costs $0.38 and a block costs $1.56. The brickyard filled a $24.80 order, w
Lisa [10]

Answer:

number of bricks = 16 and number of blocks  = 12

Step-by-step explanation:

From given information it seems , we need to determine number of bricks and number of blocks.

lets assume number of bricks = x

and number of blocks = y

since total items in brickyard is 28

⇒  number of bricks + number of blocks = 28

⇒ x + y = 28         ----------------------- equation 1

Given that cost of 1 brick = $0.38  and cost of 1 block =$1.56

so cost of x bricks = cost of 1 brick × x = 0.38x

And cost of y blocks = cost of 1 block × y = 1.56y

total cost of 28 items order = $24.80

total cost of 28 items = cost of x bricks + cost of y blocks

⇒0.38x + 1.56y = 24.80 ----------------equation 2

Now we are having following two equations

x + y = 28         ----------------------- equation 1

0.38x + 1.56y = 24.80 ----------------equation 2

from equation 1 we get x = 28 - y , substituting this value of x in equation 2 we get

0.38(28 - y) + 1.56y =  24.80

⇒10.64-0.38y+1.56y= 24.80

⇒1.18y = 24.80 - 10.64

⇒y = 14.16÷1.18 = 12

substituting value of y in equation 1 we get

x + 12 = 28

⇒x = 16

hence  number of bricks = x  = 16 and number of blocks = y = 12



4 0
3 years ago
25 Points ! Write a paragraph proof.<br> Given: ∠T and ∠V are right angles.<br> Prove: ∆TUW ∆VWU
vladimir2022 [97]

Answer:

Δ TUW ≅ ΔVWU ⇒ by AAS case

Step-by-step explanation:

* Lets revise the cases of congruent for triangles

- SSS  ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ

- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and  

 including angle in the 2nd Δ  

- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ  

 ≅ 2 angles and the side whose joining them in the 2nd Δ  

- AAS ⇒ 2 angles and one side in the first triangle ≅ 2 angles

 and one side in the 2ndΔ

- HL ⇒ hypotenuse leg of the first right angle triangle ≅ hypotenuse

 leg of the 2nd right angle Δ

* Lets solve the problem

- There are two triangles TUW and VWU

- ∠T and ∠V are right angles

- LINE TW is parallel to line VU

∵ TW // VU and UW is a transversal

∴ m∠VUW = m∠TWU ⇒ alternate angles (Z shape)

- Now we have in the two triangles two pairs of angle equal each

 other and one common side, so we can use the case AAS

- In Δ TUW and ΔVWU

∵ m∠T = m∠V ⇒ given (right angles)

∵ m∠TWU = m∠VUW ⇒ proved

∵ UW = WU ⇒ (common side in the 2 Δ)

∴ Δ TUW ≅ ΔVWU ⇒ by AAS case

7 0
2 years ago
Read 2 more answers
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