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iogann1982 [59]
3 years ago
5

Which of the following can affect the activity of enzymes?

Mathematics
2 answers:
Effectus [21]3 years ago
3 0
C temp. pH and regulatory molecules
slava [35]3 years ago
3 0

1.  B

2.  A

3. D

4. B

5. B

6. C

7. C

8. A

9. B

10. D

11. B

12. C

13. D

14. A

15. A

16. D

17. D


these are 100% correct

However make sure you are on the correct test so that you don’t put the answers incorrectly.

Hope this helps!

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Answer:

the answer i think is ba and cb

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How to write sixty nine million seventeen thousand four hundred nine
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69,017,409 is the correct answer
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Solve 73 make sure to also define the limits in the parts a and b
Aleks04 [339]

73.

f(x)=\frac{3x^4+3x^3-36x^2}{x^4-25x^2+144}

a)

\lim_{x\to\infty}f(x)=\lim_{x\to\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3\lim_{x\to-\infty}f(x)=\lim_{x\to-\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3\cdot\frac{1}{2}=3

b)

Since we can't divide by zero, we need to find when:

x^4-2x^2+144=0

But before, we can factor the numerator and the denominator:

\begin{gathered} \frac{3x^2(x^2+x-12)}{x^4-25x^2+144}=\frac{3x^2((x+4)(x-3))}{(x-3)(x-3)(x+4)(x+4)} \\ so: \\ \frac{3x^2}{(x+3)(x-4)} \end{gathered}

Now, we can conclude that the vertical asymptotes are located at:

\begin{gathered} (x+3)(x-4)=0 \\ so: \\ x=-3 \\ x=4 \end{gathered}

so, for x = -3:

\lim_{x\to-3^-}f(x)=\lim_{x\to-3^-}-\frac{162}{x^4-25x^2+144}=-162(-\infty)=\infty\lim_{x\to-3^+}f(x)=\lim_{x\to-3^+}-\frac{162}{x^4-25x^2+144}=-162(\infty)=-\infty

For x = 4:

\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty

4 0
1 year ago
Anna paid € 2800 for a dress. Payment was made after the price of the dress was reduced by 30%. What was the starting price?​
aliina [53]

Answer:

$4000

Step-by-step explanation:

so $2800 was the starting price

100%-30%=70%

So 2800=70%

2800/7=400

400=10%

400*10=$4000

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The price of a gallon of unleaded gas has dropped to
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