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3 years ago

11

Sara brought a piece of ribbion. The length of the ribbion is given in tenths. Write the length as two other equivalent fraction

s. Solve this problem any way you choose. (The meter is 6/10)

2 answers:

hram777 [196]3 years ago

8 0

Divide both 6 and 10 by 2 to get 3/5

Multiply both 6 and 10 by 2 to get 12/20

luda_lava [24]3 years ago

6 0

Good morning,

Answer:

3/5 , 60/100

Step-by-step explanation:

To get an equivalent fraction to 6/10 just multiply or divide both numerator and denominator by the same number

e.g 1 : 6/10 = (6×2)/10×2) = 3/5

e.g 2 : 6/10 = (6×10)/(10×10) = 60/100.

:)

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The diameter of the circle is 9.7 m . Calculate the length of its circumference. Round to the nearest tenth and remember to use

RSB [31]

Answer:

30.4m

Step-by-step explanation:

Diameter(D) = 2r (radius)

D = 9.7m

r = 9.7m / 2

= 4.85m

C = 2πr

= 2π × 4.85m

= 30.47344873982099m

rounding - Leave it as is if the digit in the tenth is 4 or lower

- round it up if it's 5 or higher.

~~ 30.4m

5 0

2 years ago

Dillon says that 4b and -2b are not like terms

olganol [36]

He is wrong because as long as they have the same terms/ variables behind the number it doesn’t matter about if it is positive or negative

4 0

3 years ago

I don't know how to solve this. How would I solve this? Thanks!!!!

Afina-wow [57]

Answer:

x = 11 units

Step-by-step explanation:

Area of triangle = (base + base 2) * h *1/2

so (7 + x )* 7 * 1/2 = 63

63 x 2 = 126

126 / 7 = 18

18-7 = x

x = 11

Check

(7+11)* 7 * 1/2

18* 7 = 126

126 x 0.5 = 63

CORRECT!

(p.s., tell me if wrong :P)

6 0

3 years ago

Pls help me with this math problem. WILL MARK BRAINLIEST!!!

BartSMP [9]

Answer:

50

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Given the following three points, find by the hand the quadratic function they represent (0,6, (2,16, (3,33)

Lisa [10]

Answer:

$f(x) = 4x^2 - 3x + 6$

Step-by-step explanation:

Quadratic function is given as $f(x) = ax^2 + bx + c$

Let's find a, b and c:

Substituting (0, 6):

$6 = a(0)^2 + b(0) + c$

$6 = 0 + 0 + c$

$c = 6$

Now that we know the value of c, let's derive 2 system of equations we would use to solve for a and b simultaneously as follows.

Substituting (2, 16), and c = 6

$f(x) = ax^2 + bx + c$

$16 = a(2)^2 + b(2) + 6$

$16 = 4a + 2b + 6$

$16 - 6 = 4a + 2b + 6 - 6$

$10 = 4a + 2b$

$10 = 2(2a + b)$

$\frac{10}{2} = \frac{2(2a + b)}{2}$

$5 = 2a + b$

$2a + b = 5$ => (Equation 1)

Substituting (3, 33), and c = 6

$f(x) = ax^2 + bx + x$

$33 = a(3)^2 + b(3) + 6$

$33 = 9a + 3b + 6$

$33 - 6 = 9a + 3b + 6 - 6$

$27 = 9a + 3b$

$27 = 3(3a + b)$

$\frac{27}{3} = \frac{3(3a + b)}{3}$

$9 = 3a + b$

$3a + b = 9$ => (Equation 2)

Subtract equation 1 from equation 2 to solve simultaneously for a and b.

$3a + b = 9$

$2a + b = 5$

$a = 4$

Replace a with 4 in equation 2.

$2a + b = 5$

$2(4) + b = 5$

$8 + b = 5$

$8 + b - 8 = 5 - 8$

$b = -3$

The quadratic function that represents the given 3 points would be as follows:

$f(x) = ax^2 + bx + c$

$f(x) = (4)x^2 + (-3)x + 6$

$f(x) = 4x^2 - 3x + 6$

6 0

3 years ago