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Ivahew [28]
3 years ago
5

Which descriptions from the list below accurately describe the relationship between AQRS and ATUV? Check all that apply. 284 -28

12 12 76" 176 176 1764 6 V Q A. Same sides B. Same size C. Similar D. Congruent
Mathematics
1 answer:
ololo11 [35]3 years ago
3 0

Answer:

All A to D

Step-by-step explanation:

The attachment completes the question

From the attachment,

  • it can be seen that QRS and TUV are of the same i.e. triangles

Also, from the attachment, the sides of each are:

RQ = UT = 22

QS = TV = 30

RS = UV = 23

And the angles are:

\angle Q = \angle T = 50

\angle R = \angle U = 83

\angle S = \angle V = 47

The above show that QRS and TUV are:

  • similar
  • same sides
  • and they are congruent

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Given: 6g+4a=7a<br> prove: g/a=1/2
Likurg_2 [28]

Answer:

Step-by-step explanation:

6g + 4a = 7a

⇔ 6g = 7a - 4a

⇔ 6g = 3a

Divide both side by 6a

⇒ \frac{6g}{6a} =  \frac{3a}{6a} ⇔ \frac{g}{a} = \frac{1}{2}

I hope this will help you.

3 0
3 years ago
Help with my math &lt;3
denpristay [2]
4. 1st option
5. 2nd option
8 0
3 years ago
Solve for X
Phantasy [73]

Answer:

x = 48

Step-by-step explanation:

The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

156° is an exterior angle of the triangle, then

108 + x = 156 ( subtract 108 from both sides )

x = 48

4 0
2 years ago
An airplane 30,000 feet above the ground begins descending at the rate of 2000 feet per minute. Assume the plane continues at th
Aleonysh [2.5K]
If we call y the height of the plane, we know when the time (x) is 0, the height is 30000. So let's write that in:

y = 30000 + (0)

Then, for every increase of a minute (x increases by 1), the height reduces by 2000. This can be written as:

y = 30000 - 2000x

Using what we know about y = mx+c equations, the slope of the line is -2000, and the y-intercept is (0, 30000).

4 0
3 years ago
Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 131131 millimete
matrenka [14]

Correct question:

Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 131 millimeters, and a standard deviation of 7 millimeters. If a random sample of 31" steel bolts is selected, what is the probability that the sample mean would differ from the population mean by more than 1.9 millimeters? Round your answer to four decimal places.

Answer:

0.1310

Step-by-step explanation:

Given:

Sample size, n = 31

mean, u = 131

standard deviation, \sigma = 7

X - u = 1.9

If a random sample of 31 steel bolts is selected, the probability that the sample mean would differ from the population mean by more than 1.9 millimeter, would be determined by:

Z = \frac{X-u}{\frac{\sigma}{\sqrt{n}}}

Z = \frac{1.9}{\frac{7}{\sqrt{31}}}

Z = 1.51

Probability =

P(|Z| > 1.51) =

P(Z < -1.51) + P(Z > 1.51)

= P(Z < -1.51) + 1 - P(Z > 1.51)

Using the standard normal table:

= NORMDIST(-1.51) = 0.0655;

NORMDIST(1.51) = 0.9345

Thus,

P = 0.0655 + 1 - 0.9345

= 0.1310

4 0
3 years ago
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