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erik [133]
4 years ago
10

What is the product? 6(x*2-1)(6x-1/6(x+1))

Mathematics
1 answer:
Mashcka [7]4 years ago
7 0
Answer: (x-1)(6x-1)

The number is not fully separated so the question might be interpreted in many ways. I will solve this based on assumption that the question is {6(x^2-1)(6x-1)}/{6(x+1)}

<span>{6 (x^2-1) (6x-1)}   /   {6(x+1)}
</span>{(x^2-1)(6x-1)}   /   {(x+1)}             ------> divide both by 6
{(x-1)(x+1)(6x-1)}   /   {(x+1)}           ------> (x^2-1) = (x-1)(x+1)
{(x-1)(6x-1)}   /   {1}                        ------> divide both by (x+1)

Result: (x-1)(6x-1)
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7 0
3 years ago
Jorge has some dimes and quarters. He has 10 more dimes than quarters and the collection of coins is worth $2.40. How many dimes
PIT_PIT [208]

Answer:

14 dimes and 4 quarters

Step-by-step explanation:

x= number of dimes

y=number of quarters

x-10=y

0.10x+0.25y=2.40

substitute for y

0.10x+0.25(x-10)=2.40

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3 years ago
Consider college officials in admissions registration, counseling, financial aid campus ministry, food services, and so on. How
andre [41]

Since sample size is > 40, we use the z-score in calculating for the confidence interval.

The formula is given as:

Confidence Interval = X ± z * σ / sqrt (n)

Where,

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σ = standard deviation = $10,780

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Substituting to the equation:

Confidence Interval = 50,340 ± 1.645 * 10,780 / sqrt (45)

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Its presence affects the value of mean directly. So when a data set have outliers , we prefer Median(Mid value of a data set) as the best measure of central tendency because existence of outliers does not effect Median .

Hence, the correct option is B. Outlier.

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