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2 years ago

Seth traveld 1 mile in 57.1 seconds. About how fast does Seth travel in miles per hour

1 answer:

andrey2020 [161]2 years ago

7 0

   (1 mile / 57.1 seconds) x (3,600 seconds / hour)

   =   (1 x 3,600 / 57.1) mile-seconds / seconds-hour

   = 63.05 mile/hour

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Mark bought 2 pounds of walnuts for 25.50 Approximately how much will he pay for 7 pounds of walnuts

lara31 [8.8K]

Answer:

89.25

Step-by-step explanation:

2pound of walnut= 25.50

1 pound of walnut= 12.75

7punds of walnut= 89.25

7pounds of walnut= 12.75* 7=89.25

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2 years ago

It is 4 1/2 miles to the end of the trail. If Sophia bikes to the end and back in 60 minutes, what is her average speed in miles

PtichkaEL [24]

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3 years ago

If Eight avocados cost $4. How much do 20 avocados cost?

Juliette [100K]

Answer:

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Step-by-step explanation:

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2 years ago

100 POINTS!! OMG YOU NEED TO SOLVE THIS!

natita [175]

Answer:

The correct answer is: $\Delta BDE \cong \Delta BFK$ by rule ASA rule of congruence.

Step-by-step explanation:

First let us prove $\Delta BDE \cong \Delta BFK$ by rule ASA (rule of congruence).

Congruent side:

$\overline{BD} \cong \overline{BF}$ (Given)

Congruent angles:

1. By definition of perpendicular,

$\angle{BFK} = 90 \textdegree \ (Since \ \overline{FK} \ is \ perpendicular \ to \ \overline{AB} \ (\overline{FK} \perp \overline{AB} =Given))$

Also,

$\angle{BDE} = 90 \textdegree \ (Given)$

Therefore,

$\angle{BDE} \cong \angle{BFK}$

or you can say,

$\angle{D} \cong \angle{F}$

2. Common angle between $\Delta BDE \ and \ \Delta BFK$ is $\angle{B}$

In a nutshell, in $\Delta BDE$ ,

$\angle{B}$ (Angle)

$\overline{BD}$ (Side)

$\angle{BDE}$ (Angle)

are congruent to the following angle, side and angle of $\Delta BFK$ :

$\angle{B}$ (Angle)

$\overline{BF}$ (Side)

$\angle{BFK}$ (Angle)

Therefore, by ASA rule of congruence, we can say $\Delta BDE \cong \Delta BFK$ .

Since both triangles are congruent, the sides $\overline{ED}$ and $\overline{FK}$ are also congruent.

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statuscvo [17]

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