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defon
3 years ago
13

Evaluate f(x)=3x*3+8x*2+5x-7 for remainder theorem

Mathematics
1 answer:
Mars2501 [29]3 years ago
3 0

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : 

                     x-(3*x^3+8*x^2+5*x-7)=0 

Step by step solution :<span>Step  1  :</span><span>Equation at the end of step  1  :</span><span><span> x-((((3•(x3))+23x2)+5x)-7) = 0 </span><span> Step  2  :</span></span><span>Equation at the end of step  2  :</span><span> x - (((3x3 + 23x2) + 5x) - 7) = 0 </span><span>Step  3  :</span><span>Step  4  :</span>Pulling out like terms :

<span> 4.1 </span>    Pull out like factors :

  <span> -3x3 - 8x2 - 4x + 7</span>  = 

 <span> -1 • (3x3 + 8x2 + 4x - 7)</span> 

Checking for a perfect cube :

<span> 4.2 </span>  <span> 3x3 + 8x2 + 4x - 7</span>  is not a perfect cube 

Trying to factor by pulling out :

<span> 4.3 </span>     Factoring: <span> 3x3 + 8x2 + 4x - 7</span> 

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: <span> 3x3 - 7</span> 
Group 2: <span> 8x2 + 4x</span> 

Pull out from each group separately :

Group 1: <span>  (3x3 - 7) • (1)</span>
Group 2: <span>  (2x + 1) • (4x)</span>

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The Sullivans purchased $195.60 worth of school
Sveta_85 [38]

Answer:

$11.74

Step-by-step explanation:

195.60/100 X 6 = 11.736

monetary unit so round to 2dp

11.74

8 0
3 years ago
Which four digit number is equal to its first digit raised to the power of its second digit, multiplied by its third number rais
Natasha2012 [34]
1,111 im pretty sure because 1 to the power of 1 times to the power of 1 is 1
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3 years ago
Imagine you have a pair of six-sided dice. What's the
Ksivusya [100]

Answer:

The  probability of rolling a seven or rolling an even number  as the sum of the two dice is \frac{2}{3}    

Step-by-step explanation:

Given : Imagine you have a pair of six-sided dice.

To find : What's the  probability of rolling a seven or rolling an even number  as the sum of the two dice?

Solution :

Rolling a pair of six-sided dice,

(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)

(2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

(3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)

(4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

(5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)

(6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)

Rolling a seven as the sum of the two dice are (1,6),(2,5),(3,4),(4,3),(5,2),(6,1)

Rolling an even number  as the sum of the two dice are (1,1),(1,3),(1, 5),(2, 2),(2, 4),(2, 6) ,(3, 1),(3, 3),(3, 5),(4, 2),(4, 4),(4, 6),(5, 1),(5, 3),(5, 5),(6, 2),(6, 4),(6, 6).

Favorable outcome of rolling a seven or rolling an even number  as the sum of the two dice are (1,6),(2,5),(3,4),(4,3),(5,2),(6,1), (1,1),(1,3),(1, 5),(2, 2),(2, 4),(2, 6) ,(3, 1),(3, 3),(3, 5),(4, 2),(4, 4),(4, 6),(5, 1),(5, 3),(5, 5),(6, 2),(6, 4),(6, 6) - 24

The probability is given by,

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total outcome}}

\text{Probability}=\frac{24}{36}

\text{Probability}=\frac{2}{3}

Therefore, the  probability of rolling a seven or rolling an even number  as the sum of the two dice is \frac{2}{3}

5 0
3 years ago
Twelve and nine hundredths added to two and thirty-five hundredths
Anna007 [38]

\displaystyle 12\frac{9}{100} +2\frac{35}{100} =12+\frac{9}{100} +2+\frac{35}{100} = \\\\\\ 12+2+\frac{9+35}{100} =14\frac{44}{100} =\boxed{14\frac{11}{25} }

7 0
3 years ago
Solve for x.
Galina-37 [17]

Answer:

<h2>4.4 <u><</u> x</h2>

Step-by-step explanation:

Let us break this down so we can understand it.

<h3>Step 1: Add 4 & First Answer</h3>

4.4 <u><</u> x

<h3>Step 2: Check</h3>

0.4 <u><</u> 4.4 - 4

0.4 <u><</u> 0.4 <em>Correct</em>

0.4 <u><</u> 6 - 4

0.4 <u><</u> 2 <em>Correct</em>

<h3>Step 3: Final Answer</h3>

Our final answer is 4.4 <u><</u> x

<em>PLEASE MARK BRAINLIEST</em>

8 0
4 years ago
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