All categories

3 years ago

The ratio of the lengths of corresponding sides of two similar octagons is 8:9. what is the ratio of their perimeters? *

1 answer:

5 0

The ratio of perimeters is the same as the ratio of the corresponding sides: 8:9.

_____
Any corresponding length measures of the similar figures will have the same ratio.

You might be interested in

Use Bayes' rule to find the indicated probability. The incidence of a certain disease on the island of Tukow is 4%. A new test h

lina2011 [118]

These are the events in the question above:

<span>D - has disease
</span>
<span>H - healthy (does not have disease)
</span>
<span>P - tests positive </span>

<span>It is the probability that a person has the disease AND tests positive divided by the probability that the person tests positive.
</span>
Sick, + [.04*.91] = .0364

<span>Sick, - [.04*.09] = .0036 </span>

Healthy, + [.96*.04] = 0.0384

<span>Healthy, - [.96*.96] = .9216

</span>
.0364 / (.0364 + .0.0384) = 0.487

7 0

4 years ago

A store sells a 1 1/4 pound package of turkey for $9.

aleksandrvk [35]

Answer:

$7.20

Step-by-step explanation:

The first step is to convert 1 1/4 to decimal form. 1/4=0.25, which when added to the 1 gives a total weight of 1.25 pounds. Dividing this by the price to find the unit price, you get 9/1.25=$7.20 per pound of turkey. Hope this helps!

7 0

3 years ago

Read 2 more answers

PLEASE NO LINKS DONT WASTE YOUR TIME IM NOT GONNA CLICK. Use the graph of the polynomial function to find the factored form of t

USPshnik [31]

Answer:

Step-by-step explanation:

factored form actually contains the x intercepts right in it. Basically whatever sets the whole equation equal to zero.

On the graph you can see that it passes through both positive and negative 4. so (x+4)(x-4) is the answer because plugging in 4 for x will make it zero. Same for plugging in negative 4

Hope this helps!

5 0

3 years ago

answer as a mixed number if possible. A bowl of cereal had 3 3/6 grams of sugar in it. If Victor ate 2 bowl8a week, how many gra

GrogVix [38]

<em>7 grams of sugar</em>

<h2>Explanation:</h2>

________________________________________

I'll assume your answer is as follows:

<em>A bowl of cereal had 3 3/6 grams of sugar in it. If Victor ate 2 bowl a week, how many grams of sugar would he have eaten?</em>

________________________________________

If so, then we know that:

A bowl of cereal had 3 3/6 grams of sugar in it.

Victor ate 2 bowl a week

In other words, the total of sugar he ate can be calculated as:

$3\frac{3}{6}\times2 \\ \\ Converting \ mixed \ fraction \ into \ improper \ fraction: \\ \\ =(3+\frac{3}{6})\times2 \\ \\ =(\frac{3(6)+3}{6})\times 2 \\ \\ =(\frac{21}{6})\times 2 \\ \\ =(\frac{7}{2})\times 2 \\ \\ =7$

So <em>he'd have eaten 7 grams of sugar</em>

<h2>Learn more:</h2>

Mixed numbers: brainly.com/question/383603

#LearnWithBrainly

7 0

4 years ago

A = ???? 4 −2

irinina [24]

Answer:

1. The matrix A isn't the inverse of matrix B.

2. |B|=12, |A|=12

Step-by-step explanation:

1. We want to know if matrix A is the inverse of matrix B, this means that if you do the product between B and A you have to obtain the identity matrix.

We have:

$A=\left[\begin{array}{cc}4&-2\\-1&3\end{array}\right]$

and

$B=\left[\begin{array}{cc}3&2\\1&4\end{array}\right]$

A and B are 2×2 matrices (2 rows and 2 columns), if you multiply them you have to obtain a 2×2 matrix.

Then if A is the inverse of B:

$B.A=I$

Where,

$I=\left[\begin{array}{cc}1&0\\0&1\end{array}\right]$

Observation:

If you have two matrices:

$A=\left[\begin{array}{cc}a&b\\c&d\end{array}\right]\\and\\B=\left[\begin{array}{cc}e&f\\g&h\end{array}\right]\\\\\\A.B=\left[\begin{array}{cc}(a.e+b.g)&(a.f+b.h)\\(c.e+d.g)&(c.f+d.h)\end{array}\right]$

Now:

$B.A=\left[\begin{array}{cc}3&2\\1&4\end{array}\right].\left[\begin{array}{cc}4&-2\\-1&3\end{array}\right]\\\\\\B.A=\left[\begin{array}{cc}4.3+(-2).1&4.2+(-2).4\\(-1).3+3.1&(-1).2+3.4\end{array}\right]\\\\\\B.A=\left[\begin{array}{cc}12-2&8-8\\-3+3&-2+12\end{array}\right]\\\\\\B.A=\left[\begin{array}{cc}10&0\\0&10\end{array}\right]$