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3 years ago

Solve for x: 4 over x equals 5 over 10 8 9 20 40

Mathematics

1 answer:

Sati [7]3 years ago

4 0

$\frac{4}{x} =\frac{5}{10}$ [4 over x equals 5 over 10]

Solve for x, so you need to isolate/get x by itself in the equation.

$\frac{4}{x} =\frac{5}{10}$ Multiply x on both sides

$(x)\frac{4}{x}=\frac{5}{10} (x)$

$4=\frac{5}{10} x$ Multiply the inverse of 5/10, which is 10/5, to get rid of the fraction and get x by itself

$(\frac{10}{5} )4=(\frac{10}{5} )\frac{5}{10} x$

$\frac{40}{5} =x$

8 = x

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Solve the inequality.<br><br> 2(4 + 2x) ≥ 5x + 5?<br><br> x ≤ ?

NikAS [45]

2(4+2x)≥5x+5
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3/2+2x≥5/2x (subtract 5/2 from both sides)
3/2≥1/2x (subtract 2x from both sides)
3≥x (multiply both sides by 2)
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3 years ago

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12a^3b^2 +18a²b^2 – 12ab^2<br> Factor completely

AleksAgata [21]

The factorization of 12a^3b^2 +18a²b^2 – 12ab^2 is $6 a b^{2}(a+2)(2 a-1)$

<u>Solution:</u>

Given, expression is $12 a^{3} b^{2}+18 a^{2} b^{2}-12 a b^{2}$

We have to factorize the given expression completely.

Now, take the expression

$12 a^{3} b^{2}+18 a^{2} b^{2}-12 a b^{2}$

Taking $b^2$ as common term,

$b^{2}\left(12 a^{3}+18 a^{2}-12 a\right)$

Taking "a" as common term,

$b^{2}\left(a\left(12 a^{2}+18 a-12\right)\right)$

Taking "6" as common term,

$b^{2}\left(a\left(6\left(2 a^{2}+3 a-2\right)\right)\right)$

Splitting "3a" as "4a - a" we get,

$b^{2}\left(a\left(6\left(2 a^{2}+4 a-a-2\right)\right)\right)$

$\begin{array}{l}{b^{2}(a(6(2 a(a+2)-1(a+2))))} \\\\ {b^{2}(a(6((a+2) \times(2 a-1))))} \\\\ {6 a b^{2}(a+2)(2 a-1)}\end{array}$

Hence, the factored form of given expression is $6 a b^{2}(a+2)(2 a-1)$

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3 years ago

Consider the functions f(x) = -2(x-3)² + 2 which is represented by the graph

ehidna [41]

The intervals of the function on the graph are:

Domain = (-∝, ∝)
Range = (-∝, 2]
Increases (-∝, 3]
Decreases [3, ∝)

<h3>The key features of the function?</h3>

The function is given as:

f(x) = -2(x-3)² + 2

See attachment for the graph.

From the graph, we have;

Domain = (-∝, ∝)

Because it takes all real values as its input

Range = (-∝, 2]

Because it has a vertex of (3, 2) and the vertex is a maximum

Also, it increases on the interval (-∝, 3] and decreases on the interval [3, ∝)

Read more about function interval at:

brainly.com/question/27831985

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B is the correct answer not totally sure tho hope this helps

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